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mash [69]
3 years ago
15

What is one sixth of a straight angle?

Mathematics
2 answers:
Drupady [299]3 years ago
7 0
1/6 × 180°
30°

the answer is 30°
Morgarella [4.7K]3 years ago
3 0
A straight angle is 180°. divide this by 6 to find that 30° is 1/6th
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Point (2,3) is on a circle with the center (3,5). What is the radius of the circle?
ruslelena [56]
Can you add the picture to the question?
6 0
3 years ago
Read 2 more answers
What is the percentage of 204 over 1015, 1 over 8120, 1 over 5832, and 1 over 6?
Basile [38]

Answer:

204/1015 (irreducible) = 20.1%

1/8120 (irreducible) = 0.01232%

1/5832 (irreducible) = 0.01715%

1/6 (irreducible) = 16.67%

Step-by-step explanation:

8 0
3 years ago
How can i get answers by factors of 256​
kobusy [5.1K]

Answer: Factor Pairs of 256

1 x 256 = 256.

2 x 128 = 256.

4 x 64 = 256.

8 x 32 = 256.

16 x 16 = 256.

Step-by-step explanation: These all equal up to 256

5 0
3 years ago
a study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. th
e-lub [12.9K]

Answer:

d. No because n·(1 - \hat p) = 8.96 is less than 10

Step-by-step explanation:

Question options;

a. Yes because the sample sizes of both groups are greater than 5

b. Yes, because in both cases n·\hat p > 10

c. Yes, because we know that the population is evenly distributed

d. No, because the n·(1 - \hat p) is less than 10

Explanation;

The given data are;

The number of men in the sample of men, n₁ = 41

The proportion of men who dislike anchovies, \hat p_1 = 0.67

The number of women in the sample of women, n₂ = 56

The proportion of men who dislike anchovies, \hat p_2 = 0.84

The assumptions for an analysis of the difference between means using a T-test are;

1) The data should be from a random sample of the population

2) The variables should be approximately normal (n·\hat p ≥ 10, and n·(1 - \hat p) ≥ 10)

3) The scale of the data is a continuous ordinance scale

4) The sample size should be large

5) The sample standard deviations should be approximately equal

From the requirement for normality, we have;

For the sample of men, n₁·\hat p₁  = 41 × 0.67 = 24.47 > 10

n₁·(1 - \hat p₁) = 41 × (1 - 0.67) = 13.53 > 10

For the sample of women, n₂·\hat p₂  = 56 × 0.84 = 47.04 > 10

n₂·(1 - \hat p₂) = 56 × (1 - 0.84) = 8.96 < 10

Therefore, the for n₂·(1 - \hat p₂), the sample does not meet the requirement for normality

The correct option is d. No because n₂·(1 - \hat p₂) = 8.96 is less than 10

3 0
3 years ago
I need some help on finding the area
Advocard [28]

Answer:

5x+15

Step-by-step explanation:

area=Length X Width

area= 5   X   x+3

area=5(x+3)

area=5x+15

7 0
3 years ago
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