Answer:
Step-by-step explanation:
The identities you need here are:
and 
You also need to know that
x = rcosθ and
y = rsinθ
to get this done.
We have
r = 6 sin θ
Let's first multiply both sides by r (you'll always begin these this way; you'll see why in a second):
r² = 6r sin θ
Now let's replace r² with what it's equal to:
x² + y² = 6r sin θ
Now let's replace r sin θ with what it's equal to:
x² + y² = 6y
That looks like the beginnings of a circle. Let's get everything on one side because I have a feeling we will be completing the square on this:

Complete the square on the y-terms by taking half its linear term, squaring it and adding it to both sides.
The y linear term is 6. Half of 6 is 3, and 3 squared is 9, so we add 9 in on both sides:

In the process of completing the square, we created within that set of parenthesis a perfect square binomial:

And there's your circle! Third choice down is the one you want.
Fun, huh?
Answer:
False
Step-by-step explanation:
If we have a factor then the remainder after the division will be zero.
Answer:
whut
Step-by-step explanation:
First, we need to solve for sin(67°) = 22/x. Multiply each side by x and divide each side by sin(67°)
x = 22/sin(67°) = 23.9
Use pythagorean theorem to find the last side.
a^2 + 22^2 = 23.9^2
a^2 + 484 = 571.21. Subtract each side by 484
a^2= 87.21. Take the square root of each side.
a = 9.3
x = 23.9 and the other side is 9.3