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Leni [432]
3 years ago
10

What is the inverse function of f(x) = x

Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

y = x

Step-by-step explanation:

The inverse of f(x) = x is just y = x.

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Solve the equation for x. 2x + 22 = 4(x+3)
shusha [124]

Answer:

x = 5

Step-by-step explanation:

We have the algebraic expression and are asked to solve for x.

To solve, we need to isolate x.

2x + 22 = 4(x + 3)

Distribute :

2x + 22 = (4(x) + 4(3))

2x + 22 = 4x + 12

Subtract 12 from both sides :

2x + 10 = 4x

4x = 2x + 10

Subtract 2x from both sides :

2x = 10

Divide 2 from both sides to get x alone :

x = 5

5 0
2 years ago
Read 2 more answers
If a password must have two letters and three digits how many different passwords are possible? ​
Aleks [24]

Answer:

6

Step-by-step explanation:

8 0
2 years ago
in fred's catering order 5/12 of the lunches are sandwiches 2/12 are salads and 4/12 are pastas. Which equation can be used to f
GarryVolchara [31]

We can express an equation to find the fraction of the catering order that is sandwiches or salads by summing up the fractions of the sandwiches and the salads, in this case, the fraction of the sandwiches is 5/12 and the fraction of the salads is 2/12, then the equation looks like this:

c = 5/12 + 2/12, option B is the correct answer

7 0
1 year ago
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
Which expression is equivalent to -36 - 8?
Deffense [45]
-36-8 = -44

-36+(-8) = -44
third option
7 0
2 years ago
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