3 years ago

How do you solve this ?

Mathematics

1 answer:

ss7ja [257]3 years ago

4 0

Answer:

q=7.7

Step-by-step explanation: This is trigonometry and you would use cosine since you have H (29) as your known and A (q) as your unknown. You would do cos(39)29=7.7

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4 0

3 years ago

What is the solutions to the equation?

victus00 [196]

Hi,

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$x^{3} + 3x^{2} - 4x - 12 = 0 \\ {x}^{2} \times (x + 3) - 4x - 12 = 0 \\ {x}^{2} \times (x + 3) - 4(x - 3) = 0 \\ (x + 3) \times ( {x}^{2} - 4) = 0 \\ x + 3 = 0 \\ {x}^{2} - 4 = 0 \\ \\ (results) \\ x1 = - 3 \\ x2 = - 2 \\ x3 = 2$

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3 years ago