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3 years ago

15

How do you solve this ?

1 answer:

ss7ja [257]3 years ago

4 0

Answer:

q=7.7

Step-by-step explanation: This is trigonometry and you would use cosine since you have H (29) as your known and A (q) as your unknown. You would do cos(39)29=7.7

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The length of a parking Lot is 5 yards more than the width. If the area of the parking lot is 66 square yards, find the dimensio

Brums [2.3K]

Answer:

6 yards by 11 yards

Step-by-step explanation:

Factors of 66 are ...

66 = 1·66 = 2·33 = 3·22 = 6·11

The last pair of factors differ by 5, so represent the solution to the problem.

The width of the parking lot is 6 yards; the length is 11 yards.

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3 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

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3 years ago

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trasher [3.6K]

X= 25.65 + 16.5 - 12.45
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3 years ago

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9+9000000+90+900+9000+90000+900000+1

anyanavicka [17]

Answer:

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Step-by-step explanation:

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3 years ago

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arlik [135]

Answer:

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Step-by-step explanation:

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2 years ago

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