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Ymorist [56]
3 years ago
8

State the null and alternative hypotheses for the situation described below for a statistical test. Your answer should be an exp

ression composed of symbols: Testing to see if average sales are higher in stores where customers are approached by salespeople than in stores where they aren't. Let group 1 be the group of stores where customers are approached by salespeople and let group 2 be the group of stores where customers are not approached by salespeople.
Mathematics
1 answer:
garik1379 [7]3 years ago
5 0
Null: mu1=mu2
Alternative: mu1>mu2
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Write an equation in slope-intercept form of a line that contains points (2-4)<br> and (5,8)
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Answer:

y = 4x - 12

Step-by-step explanation:

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3 years ago
2.5% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac
Aleks04 [339]

Answer:

P(disease/positivetest) = 0.36116

Step-by-step explanation:

This is a conditional probability exercise.

Let's name the events :

I : ''A person is infected''

NI : ''A person is not infected''

PT : ''The test is positive''

NT : ''The test is negative''

The conditional probability equation is :

Given two events A and B :

P(A/B) = P(A ∩ B) / P(B)

P(B) >0

P(A/B) is the probability of the event A given that the event B happened

P(A ∩ B) is the probability of the event (A ∩ B)

(A ∩ B) is the event where A and B happened at the same time

In the exercise :

P(I)=0.025

P(NI)= 1-P(I)=1-0.025=0.975\\P(NI)=0.975

P(PT/I)=0.904\\P(PT/NI)=0.041

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

P(PT/I)=0.904

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

P(PT∩ I) = 0.0226

P(PT/NI)=0.041

P(PT/NI)=P(PT∩ NI)/P(NI)

0.041=P(PT∩ NI)/0.975

P(PT∩ NI) = 0.041 x 0.975

P(PT∩ NI) = 0.039975

P(PT) = P(PT∩ I)+P(PT∩ NI)

P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116

8 0
2 years ago
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zavuch27 [327]

Answer:

H

Step-by-step explanation:

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