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DIA [1.3K]
2 years ago
11

Find all of the missing sides or angles in the right triangle

Mathematics
1 answer:
shutvik [7]2 years ago
4 0
Tan(29°) = opposite/adjacent = AC/CB  ⇒
CB = AC/tan(29°) = 20/0.5543 ≈ 36.08

sin(29°) = opposite/hypotenuse = AC/AB  ⇒
AB = AC/sin(29°) = 20/0.4848 ≈ 41.25

∠A = 180 - ∠B - ∠С = 180 - 29 - 90 = 61°

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leonid [27]
(3*2)(10^2 * 10^3) = 6*10^5
4 0
3 years ago
Suppose f (x) = x^2. Find the graph of f(x+2)
NISA [10]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)={{  A}}({{  B}}x+{{  C}})+{{  D}}
\\\\
~~~~y={{  A}}({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)={{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\\\
f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\\\
f(x)={{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
~~~~~~if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
~~~~~~if\ {{  D}}\textit{ is negative, downwards}\\\\
~~~~~~if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind,

\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}

C = 2         B = 1        C/B = 2/1 or +2,    horizontal left shift of 2 units

f(x) shifted left by 2 units is f(x+2).
8 0
2 years ago
1.) Write the slope-intercept form of the equation for the line.
Vinvika [58]

Answer:

Step-by-step explanation:

4 0
3 years ago
Answer this in two minutes
gregori [183]

Hey there! :)

Answer:

y = x - 3.

Step-by-step explanation:

Given:

Slope = 1

Point on line: (8, 5)

Plug these into the formula y = mx + b, where:

m = slope

x = x coordinate of point

y = y coordinate of point

5 = 1(8) + b

5 = 8 + b

Subtract both sides by 8:

5 - 8 = 8 -8 + b

-3 = b

Rewrite the equation:

y = x - 3.

4 0
3 years ago
A planr leaves and flies due north at 280 miles per hour. AT the same time another plane takes off from the same airport and fli
kompoz [17]

Answer:

Distance between the two planes after 1 hour = 410 miles

Step-by-step explanation:

Given - A plane leaves and flies due north at 280 miles per hour. At

            the same time another plane takes off from the same airport

            and flies due east at a speed of 300 miles per hour.

To find - What is the distance between the two planes after 1 hour ?

Proof -

Given that , Plane 1 flies due north at a speed of 280 miles per hour.

So,

Total distance traveled in 1 hour = 280 miles

Also,

Plane 2 flies due east at a speed of 300 miles per hour.

So,

Total distance traveled in 1 hour = 300 miles.

The diagram is as follows :

Now,

We have to find the distance after 1 hour i.e. AC

In Triangle ABC ,

By using Pythagoras theorem, we get

AC² = BC² + AB²

⇒AC² = (300)² + (280)²

⇒AC² = 90,000 + 78,400

⇒AC² = 168,400

⇒AC = √168,400

⇒AC = 410.366 ≈ 410

∴ we get

Distance between the two planes after 1 hour = 410 miles

7 0
3 years ago
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