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3 years ago

Find all of the missing sides or angles in the right triangle

Mathematics

1 answer:

shutvik [7]3 years ago

4 0

Tan(29°) = opposite/adjacent = AC/CB ⇒
CB = AC/tan(29°) = 20/0.5543 ≈ 36.08

sin(29°) = opposite/hypotenuse = AC/AB ⇒
AB = AC/sin(29°) = 20/0.4848 ≈ 41.25

∠A = 180 - ∠B - ∠С = 180 - 29 - 90 = 61°

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