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Ierofanga [76]
3 years ago
9

What is the vertex of the graph of y = –x2

Mathematics
2 answers:
REY [17]3 years ago
7 0

Answer:

Vertex : ( 0, 0).

Step-by-step explanation:

Given  : y = –x².

To find: What is the vertex of the graph.

Solution : We have given parabolic equation :  y = –x².

Vertex form of parabola: y = ( x -h)² + k.

Where, ( h ,k )  are vertex.

On comparing y = –x² with  y = ( x -h)² + k.

h= 0 , k= 0.

Vertex : ( 0, 0)

Therefore, Vertex : ( 0, 0),

dolphi86 [110]3 years ago
6 0
The parabola goes down(makes a sad face) because it is negative. The answer is 0,0
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What is the sum of the following numbers. -7,5,-3,6,-4,7,-5,3-1,4​
Sav [38]

Answer:

Step-by-step explanation:

Tổng : -7,5+(-3,6)+(-4,7)+(-5,3)+(-1,4)=-22,5

3 0
2 years ago
Another easy question need fast please
Tresset [83]

Answer:

30.25

Step-by-step explanation:

All angles of a line must add up to 180. Since we already know that one angle is 90 degrees, we know that the other angles should add up to 90 degrees in order for all of the angles to add up to 180 degrees:

(3x-7)+(x+8)=90

4x+1=90

4x=89

x=22.25

22.25+8= 30.25

3 0
2 years ago
PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the
drek231 [11]

Answer:

1) The height of the ball from 0 to 5  seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2)  The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0
3 years ago
Find the value of x.
Cerrena [4.2K]
x^2 + (x + 3)^2 = (\sqrt{117})^2

x^2 + x^2 + 6x + 9 = 117

2x^2 + 6x -108 = 0

x^2 + 3x - 54 = 0

(x + 9)(x - 6) = 0

x + 9 = 0 ~~or~~ x - 6 = 0

x = -9 ~~ or~~ x = 6

Since the side of a triangle cannot have a negative length, we discard the solution x = -9.

Answer: x = 6
3 0
3 years ago
Read 2 more answers
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krok68 [10]
The answer this problem is -247
6 0
3 years ago
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