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lisov135 [29]
3 years ago
14

How do you find the constant of variation when y=-(2/3) and x=3

Mathematics
2 answers:
ololo11 [35]3 years ago
7 0
y=-\frac{2}{3};\ x=3\\\\kx=y\\\\3k=-\frac{2}{3}\ \ \ \ /:3\\\\k=-\frac{2}{9}
Katyanochek1 [597]3 years ago
6 0
You can't. If you think about the straight line on a graph, those numbers
describe a single point that the line goes through, and they don't tell you
anything about the slope of the line, or where it crosses the x-axis or the
y-axis.  So I don't think you can tell the constant of variation from one point.
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A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla
Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

\frac{4}{12} * \frac{8}{11} =   \frac{32}{132} or 0.2424 or 24.24%

8 0
3 years ago
The inequality of 8z+3-2z<51 is
masya89 [10]
8z - 2z < 48
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8 0
3 years ago
0.3, 0.08, 0.003, 0.83<br> In order from smallest to largest
pishuonlain [190]
0.003, 0.08, 0.3, 0.83
3 0
2 years ago
Read 2 more answers
A helium-filled blimp stays aloft since helium is less dense than regular air, so helium will rise above regular
worty [1.4K]

Answer:

The blimp can carry 70 passengers

Step-by-step explanation:

Lets use the ratio method to solve this problem

∵ 1 cubic meter of helium  can lift about 1.1 kg

∵ A blimp can carry as much as 2 x 10^{5} m³ of helium

By using the ratio method

→  m³         :  kg

→  1            :  1.1

→  2 x 10^{5}   :  x

By using cross multiplication

∴ x × 1 = 1.1 × 2 x 10^{5}

∴ x = 2.2 x 10^{5}

∵ x represents the mass that can carried by the helium

∴  2 x 10^{5} m³ of helium can lift 2.2 x 10^{5} kg

∵ The mass of the blimp is 2.13 x 10^{5} kg

- Subtract the mass of the blimp from the mass that the given

    amount of helium can lift to find the mass of the passengers

∴ The mass of the passengers = 2.2 x 10^{5} - 2.13 x 10^{5}

- Subtract 2.13 from 2.2 ⇒ 2.2 - 2.13 = 0.07

∴ The mass of the passengers = 0.07 x 10^{5}

∵ The average mass of a person with luggage is 10² kg

- Divide the mass of the passengers by the mass of the person

   to find the number of the passengers

∴ The number of passengers = 0.07 x 10^{5} ÷ 10²

- Subtract the exponents of 10 to find the answer

∵ 10^{5} ÷ 10² = 10^{5-2} = 10³

∴ The number of passengers = 0.07 x 10³

∴ The number of passengers = 0.07 × 1000

∴ The number of passengers = 70

The blimp can carry 70 passengers

3 0
3 years ago
I’ll give brainliest but I just need help
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ITS THE 1ST ROW KING
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