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lisov135 [29]
3 years ago
14

How do you find the constant of variation when y=-(2/3) and x=3

Mathematics
2 answers:
ololo11 [35]3 years ago
7 0
y=-\frac{2}{3};\ x=3\\\\kx=y\\\\3k=-\frac{2}{3}\ \ \ \ /:3\\\\k=-\frac{2}{9}
Katyanochek1 [597]3 years ago
6 0
You can't. If you think about the straight line on a graph, those numbers
describe a single point that the line goes through, and they don't tell you
anything about the slope of the line, or where it crosses the x-axis or the
y-axis.  So I don't think you can tell the constant of variation from one point.
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Answer:

\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}

Step-by-step explanation:

Given

\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}

Required

Fill in the gaps

Going by the given parameters, we have that

\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}

x^2 - 9x + 8, when factorized is (x-1)(x-8)

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