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Tom [10]
3 years ago
13

PLZZZZZZZZZZZZZZZZZZZZZZZZZ! help i need it now PLZZZZZZZZZZZZZZZZZZZZ

Mathematics
1 answer:
vova2212 [387]3 years ago
3 0

here is the true answer for anyone looking.

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It cost $7.00 to enter the football game. A
bixtya [17]

Answer: 4

Step-by-step explanation:

First, you have to pay to get in the game ($15 - $7) and then you have $8 left. Each snack is $2, so for $8 you can get 4 snacks (2x4=8)

8 0
3 years ago
The function f(x)=3(2.5)^x is shown on the coordinate plane.
Simora [160]
The function f(x)=3(2.5)^x is shown on the coordinate plane.

Select from the drop-down menus to correctly describe the end behavior of f(x) .


As x increases without bound, the graph of f(x) increases without bound
3 0
4 years ago
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Y-2 = -3(x + 6), write the equation of the line in slope intercept form.
bija089 [108]

Answer: y=-3x-16

Step-by-step explanation:

Slope-intercept form is y=mx+b, where m is slope and b is y-intercept.

y-2=-3(x+6)        [distribute]

y-2=-3x-18          [add both sides by 2]

y=-3x-16

Now, we see that the equation above matches the slope-intercept form equation. You can see that m=-3 and b=-16.

4 0
3 years ago
HELP PLEASEEEEEEE <br><br> can you help me find the period of the function from this table?
satela [25.4K]

Answer: It’s either 6, or 2, though the answer is most likely 6, because of the way the table is created.

Step-by-step explanation:

8 0
3 years ago
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Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3
MAXImum [283]

Observe that

\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v

In the original equation, divide both sides by \dfrac12:

-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2

\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2

Next,

\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi

where n is any integer. Then

\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi

Fix n=0 to ensure -\pi, so that

v=-\dfrac\pi6,v=-\dfrac\pi2

3 0
4 years ago
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