Answer:
A. 110 pounds,
C. 281 pounds
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A measure is said to be an outlier if it has a pvalue lesser than 0.05 or higher than 0.95.
In this problem, we have that:
A. 110 pounds,
has a pvalue of 0.0179. So a weight of 110 pounds is an outlier.
B. 157 pounds,
has a pvalue of 0.702.
So a weight of 157 is not an outlier.
C. 281 pounds
has a pvalue of 0.9988.
So a weight of 281 is an outlier.
i dont know so yeah sorry my guy
Step-by-step explanation:
5x-16 = 4(x-8)-3x
first expand what is in parenthesis
4(x-8) = 4x-32
so now you have 5x-16 = 4x-32-3x
subtract 3x from 4x on the right side of equation 4x-3x = x
5x-16 = x -32
subtract 1x from each side to get
4x-16 = -32
add 16 to both sides to get 4x=-16
x = -16/4 = -4
x=-4
Answer:
3.468 × 10^3
Step-by-step explanation:
Answer: See explanation
Step-by-step explanation:
a. Construct a decision tree for Wile
The solution to the question has been attached.
b. What is the expected value of the new car?
= [(0.2 × $10,000) + (0.8 × $18,000)] - $22,000
= $2000 + $14400 - $22000
= $16400 - $22000
= -$5600
c. What is the expected value of the used car?
= [(0.4 × $4000) + (0.6 ×$9000] - $12000
= $1600 + 5400 - $12000
= $7000 - $12000
= -$5000
d. What is the expected value of leasing the car?
= [(0.1 × -$2000) + (0.9 ×0)] - $8500
= -$200 - $8500
= -$8700
