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bekas [8.4K]
4 years ago
10

Find the minimum value of C=2x+y subject to the following constraints: Please help me!!

Mathematics
1 answer:
-BARSIC- [3]4 years ago
7 0

Answer:

The minimum value of C is 20

Step-by-step explanation:

we have

2x+3y\geq 24 ----> constraint A

4x+y\geq 38 ----> constraint B

x\geq 0 ----> constraint C

y\geq 0 ----> constraint D

Using a graphing tool

The solution set of the constraints is the shaded area

see the attached figure

The vertices of the shaded area are (0,38),(9,2) and (12,0)

To determine the minimum value of C substitute the values of x and y of each vertex in the objective function and then compare the results

C=2x+y

For (0,38) ---> C=2(0)+38=38

For (9,2) ---> C=2(9)+2=20

For (12,0) ---> C=2(12)+0=24

therefore

The minimum value of C is 20

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Fill in the boxes to complete the addition. 3/5+1/4
Fynjy0 [20]

Answer:

3/5 + 1/4 = 17/20

Step-by-step explanation:

  • \frac{3}{5} + \frac{1}{4}
  • LCM is 20
  • \frac{12}{20} + \frac{5}{20}
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7 0
3 years ago
I need help with this question it is on mathswatch btw.
navik [9.2K]

Answer:

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Step-by-step explanation:

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2 years ago
Rewrite this radicand as two factors, one of which is a perfect square.
seropon [69]

Answer:

2 \sqrt{15}

Step-by-step explanation:

1) rewrite 60 as it's prime factors.

\sqrt{2 \times 2 \times 3 \times } 5

2) group the smae prime factors into pairs.

\sqrt{(2 \times 2)}  \times 3 \times 5

3) Rewrite each pair in exponent form.

\sqrt{ {2}^{2} \times 3 \times 5 }

4) use this role:

\sqrt{ {x}^{2} }  = x

2 \sqrt{3 \times 5}

5) Simplify.

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So, therefor, the answer is option 1.

5 0
3 years ago
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Express a ratio in the form of 1:n<br> 5:45
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Answer:

1:9

Step-by-step explanation:

you divide both sides by the right number

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6 0
2 years ago
Mold grows on bread and every day it doubles by the eighth day the entire bread is covered with mold when was half the bread cov
Brut [27]

Answer:

The mold will cover half the area as much are one day before it.

Step-by-step explanation:

Given:

Every day the mold on bread grows doubles

And by 8th day entire bread covered with it.

To Find:

When was half the bread covered by mold.

Solution:

It is said that area covered by mold doubles on each day

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So on previous day it should What ever area on 8th day/2

i.e A(8)/2

Similar on 6th day A(7)/2

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On 1st =A(2)/2

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<em>One day before the 8th day will be 7th day</em>

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4 0
3 years ago
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