Question

7. Un electrón es proyectado horizontalmente con una aceleración, entra en un campo

Answer 1

Answer:

$a=4.93\times 10^{14}\ m/s^2$

Step-by-step explanation:

In this question,

Force on the electron is $4.5\times 10^{-16}\ N$

Mass of the electron is $9.11\times 10^{-31}\ kg$

Net force, F = ma

So,

$a=\dfrac{F}{m}\\\\4.5\times 10^{-16}\ N=9.11\times 10^{-31}\ kg\times a\\\\a=\dfrac{4.5\times 10^{-16}}{9.11\times 10^{-31}}\\\\a=4.93\times 10^{14}\ m/s^2$

So, the acceleration of the electron is $4.93\times 10^{14}\ m/s^2$.