I don’t really know exactly to what degree you need to put in your solution. But I rounded to the nearest tenth degree.
A = 112 degrees
B= 28 degrees (180-112-40 bc all sides of a triangle must equal 180)
C= 40
a= 27.6 (this is the side opposite of angle A)
b= 14 (side opposite b)
c= 19.2 (side opposite c)
HOW TO SOLVE:
c= law of sines, so c/sin(40) = 14/sin(28), multiply both sides by sin(40) so c can be isolated and solved for. c = 14sin(40)/sin(28). Plug into calculator then get answer. c is approximately 19.2.
a = law of sines again, so a/sin(112) = 14/sin(28). Multiply both sides again by sin(112) then solve. a = 14sin(112)/sin(28). Calculator again. a is around 27.6
Answer:
n= 75
y= 75
z= 50
p= 105
other n across from p= 105
Step-by-step explanation:
n and y are the same since the triangle is isoseles.
p is supplemetary to n
z and 50 are opposites in a quadrilateral
Answer:
Irregular polygons are polygons that do not have equal sides or equal angles. When finding the area of an irregular polygon, partition the polygon into smaller regular polygon shapes. You can then plug those measurements into their respective area formulas and multiply to find the area of one part of the shape.
This is 16cm.
Answer:
One number is 15 and 3 less than that is 12 so that is your other number
