All categories

3 years ago

Write an equation in slope-intercept form for the line that passes through (6, 6) and is perpendicular to -2x + 3y = -6

Mathematics

1 answer:

Butoxors [25]3 years ago

6 0

I think it is -3 = 1/2x - y

I included the work as well.

You might be interested in

Solve for substitution<br> x-2y+z=-11<br> 3x+2y-z=7<br> -x+2y+4z=-9

Alla [95]

Answer:

Unit rate miles per day is, 3

Step-by-step explanation:

Unit rate are defined as the rate are expressed as quantity of 1 such that 2 miles per hour or 5 km per hour.

As per the given statement: A construction crew built 1/2 miles of road in 1/6 days

by unit rate definition;

After substituting the given values we have

⇒

Therefore, unit rate miles per day is, 3

Step-by-step explanation:

hhhthhg

6 0

3 years ago

Https://cook.owschools.com/media/g_alg02_ccss_2016/4/q16210.gif

labwork [276]

Im assuming your supposed to find like terms soo... as my final answer i got 11m-3n-13

3 0

3 years ago

QUESTION 7 of 10: You begin the week with 30 units of orange juice. You purchase 50 units. Your ending inventory for the week is

Feliz [49]

Answer d)50 because 30+50=80. 80-30=50

7 0

2 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago

What is 2x-y=6 the slope

Flura [38]

First of all, lets get y on its own side of the equation.

$-y=-2x+6\\y=2x-6\\$

This is slope intercept form, y=mx+b, where m is slope.

we can see that m=2, so the slope is 2 or $\frac{2}{1}$

5 0

2 years ago

Read 2 more answers