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Sauron [17]
3 years ago
11

WILL GIVE BRAINLIEST!!! What is the value of x?

Mathematics
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

42.9 m

Step-by-step explanation:

check out the image for proper explanation.

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Factor the polynomial.<br> 13x² – 20x – 12
erma4kov [3.2K]

Answer:

(13 x + 6) (x - 2)

Step-by-step explanation:

Factor the following:

13 x^2 - 20 x - 12

Factor the quadratic 13 x^2 - 20 x - 12. The coefficient of x^2 is 13 and the constant term is -12. The product of 13 and -12 is -156. The factors of -156 which sum to -20 are 6 and -26. So 13 x^2 - 20 x - 12 = 13 x^2 - 26 x + 6 x - 12 = x (13 x + 6) - 2 (13 x + 6):

x (13 x + 6) - 2 (13 x + 6)

Factor 13 x + 6 from x (13 x + 6) - 2 (13 x + 6):

Answer: (13 x + 6) (x - 2)

6 0
3 years ago
mrs.fowler suggested contacting a travel agent to see whether they could get a lower price. the agent found a price that was 30%
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0.3 x 2075. Use a calculator.
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2 years ago
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Is my answer correct?
kotykmax [81]

Answer:

The short answer is: yes, the answer to "How do you do?" is "How do you do?" It is also acceptable to reply "I'm fine, and you?" and similar variations. However -- and this is important to the etiquette side of things and not so much the language side -- "how do you do?" is actually not a question!

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2 years ago
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Can someone help me please
Ghella [55]
X=-y+10/7y
Here’s a picture on how I solve and got my answer

7 0
3 years ago
2. When Joey dives off a diving board, the equation of his pathway can be modeled by h = -16- + 15 + 12.
Sergeu [11.5K]

Answer:

a) The maximum height is approx 15.5 unit.

b) The time it will take for Joey to reach the water is 1.45 hour.

Step-by-step explanation:

Given : When Joey dives off a diving board, the equation of his pathway can be modeled by h(t)= -16t^2+15t + 12

To find : a) Find Joey's maximum height.

b) Find the time it will take for Joey to reach the water.

Solution :

Modeled  h(t)= -16t^2+15t + 12 ....(1)

a) To find maximum height

Derivate (1) w.r.t. t,

h'= -32t+15

For critical point put h'=0,

-32t+15=0

t=\frac{15}{32}

t=0.46875

Derivate again w.r.t. t,

h''= -32

It is maximum at t=0.46875.

Substitute t in equation (1),

h(0.46875)= -16(0.46875)^2+15(0.46875)+12

h(0.46875)= -3.515625+7.03125+12

h(0.46875)= 15.515625

The maximum height is approx 15.5 unit.

b) To find the time it will take for Joey to reach the water.

Put h=0 in equation (1),

-16t^2+15t + 12=0

Apply quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=-16 , b=15, c=12

t=\frac{-15\pm\sqrt{(15)^2-4(-16)(12)}}{2(-16)}

t=\frac{-15\pm\sqrt{225+768}}{-32}

t=\frac{-15\pm\sqrt{993}}{-32}

t=\frac{-15+\sqrt{993}}{-32},\frac{-15-\sqrt{993}}{-32}

t=−0.515,1.453

Reject negative value.

The time is t=1.45.

The time it will take for Joey to reach the water is 1.45 hour.

5 0
3 years ago
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