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3 years ago

Simplify the expression (3x^4/2y^3)^2

1 answer:

8 0

Simplify the following:
((3 x^4 y^3)/2)^2
Multiply each exponent in (3 x^4 y^3)/2 by 2:
(3^2 x^(2×4) y^(2×3))/(2^2)
2×4 = 8:
(3^2 x^8 y^(2×3))/2^2
2×3 = 6:
(3^2 x^8 y^6)/2^2
2^2 = 4:
(3^2 x^8 y^6)/4
3^2 = 9:
Answer: (9 x^8 y^6)/4

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Describe the transformation that changes triangle ABC to triangle A'B'C

Nonamiya [84]

It is a down shift of 3.
Also written as (x, y-3)

4 0

3 years ago

Find the equation of a line with m = 3 that passes though the point (-12,<br> 4).

Viefleur [7K]

Answer:

y = 3x + 40

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 3 , then

y = 3x + c ← is the partial equation

To find c substitute (- 12, 4 ) into the partial equation

4 = - 36 + c ⇒ c = 4 + 36 = 40

y = 3x + 40 ← equation of line

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2 years ago

The student-to-faculty ratio at a small collage is 17:3. The total number of students and faculty is 740. How many faculty membe

kozerog [31]

There are 111 faculty members at the college and 629 students at the college.

Step-by-step explanation:

Given,

The student to faculty ratio = 17:3

Total number of 740.

Let,

x be the original number.

Number of students = 17x

Number of faculty = 3x

Number of students + Number of faculty = 740

$17x+3x=740\\20x=740$

Dividing both sides by 20

$\frac{20x}{20}=\frac{740}{20}\\x=37$

Number of students = 17x = 17*37 = 629

Number of faculty = 3x = 3*37 = 111

There are 111 faculty members at the college and 629 students at the college.

Keywords: ratio, multiplication

Learn more about multiplications at:

#LearnwithBrainly

6 0

3 years ago

How to find the area of the shaded region

Andreas93 [3]

Y=2x^(1/2)

A=2⌠x^(1/2) dx

A=2[ (2/3)x^(3/2) ]

A=(4/3)[ x^(3/2) ] x=[1,4]

A=(4/3)(8-1)

A=(4/3)7

A=28/3 u^2

A=9 1/3 u^2

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3 years ago

The projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is

Tom [10]

Answer: 0=-4.9t²+19.6t+24.5

Step-by-step explanation:

$s(t)=gt^2+v_0t+s_0\\v_0=19,6\ \frac{m}{s} \ \ \ \ s_0=24,5\ m\ \ \ \ g=-4,9\ \frac{m}{s^2} \ \ \ \ S(t)=0\ (the\ object \ hitts\ the \ ground)\ \Rightarrow\\0=-4,9t^2+19,6t+24,5.$

4 0

2 years ago