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Scilla [17]
3 years ago
5

Simplify the expression (3x^4/2y^3)^2

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0
Simplify the following:
((3 x^4 y^3)/2)^2
Multiply each exponent in (3 x^4 y^3)/2 by 2:
(3^2 x^(2×4) y^(2×3))/(2^2)
2×4 = 8:
(3^2 x^8 y^(2×3))/2^2
2×3 = 6:
(3^2 x^8 y^6)/2^2
2^2 = 4:
(3^2 x^8 y^6)/4
3^2 = 9:
Answer: (9 x^8 y^6)/4
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According to a Pew Research Center, in May 2011, 35% of all American adults had a smart phone (one which the user can use to rea
Veronika [31]

Answer:

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

Step-by-step explanation:

Data given

n=300 represent the random sample taken

X=120 represent the people who have a smart phone

\hat p=\frac{120}{300}=0.4 estimated proportion of people who have a smart phone

p_o=0.35 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to test the claim that the true proportion of people who have a smart phone is higher than 0.35, the system of hypothesis are.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82  

Statistical decision  

Since is a right tailed test the p value would be:  

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

4 0
3 years ago
What is 5×5+9+2+2-4+6-2-3
devlian [24]
Pemdas
mutliply first
5*5=25
now we have
25+9+2+2-4+6-2-3
34+2+2-4+6-2-3
36+2-4+6-2-3
38-4+6-2-3
34+6-2-3
40-2-3
38-3
35
5 0
3 years ago
https://tex.z-dn.net/?f=%286%29%5C+%5C+%5C+f%28x%29%3Dax%5E2%5C+%5C+%5C+and%5C+%5C+%5C+f%282%29%3D48%5C%5C.%5C+%5C+%5C+%5CRighta
snow_tiger [21]

Answer:

What the what???????




4 0
3 years ago
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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
What is the median of the following data values 98,102,53,80,22
timurjin [86]

Answer:

80

Step-by-step explanation:

8 0
3 years ago
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