All categories

3 years ago

Simplify the expression (3x^4/2y^3)^2

1 answer:

8 0

Simplify the following:
((3 x^4 y^3)/2)^2
Multiply each exponent in (3 x^4 y^3)/2 by 2:
(3^2 x^(2×4) y^(2×3))/(2^2)
2×4 = 8:
(3^2 x^8 y^(2×3))/2^2
2×3 = 6:
(3^2 x^8 y^6)/2^2
2^2 = 4:
(3^2 x^8 y^6)/4
3^2 = 9:
Answer: (9 x^8 y^6)/4

You might be interested in

What is the domain and range of the relation shown in the table?

seropon [69]

Domain is the set of x values and range is the set of y values

Domain: {-1, 0, 4}

Range: { 2, 3, 4, 7}

Answer is the first one

4 0

3 years ago

Read 2 more answers

There are 3 windows in Tiana’s house that are made up of squares of colored glass. Each square of colored glass is the same size

Sati [7]

The answer is in your brain

7 0

2 years ago

Factorise: (Using Algebraic Identities)<br> 64x^3-(4x-3y)^3

Naddika [18.5K]

Answer:

9y(16x2−12xy+3y2)

Step-by-step explanation:

Factor 64x3−(4x−3y)3

144x2y−108xy2+27y3

=9y(16x2−12xy+3y2)

Answer:

9y(16x2−12xy+3y2)

6 0

2 years ago

Solve the formula for the indicated variable. EASY 40 POINTS!!!!!!!!!!!!!!!!

vlada-n [284]

Answer:

d = Nc + x

Step-by-step explanation:

Given

N = $\frac{d-x}{c}$

Multiply both sides by c to clear the fraction

Nc = d - x ( add x to both sides )

Nc + x = d

8 0

3 years ago

Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?

Artemon [7]

Answer:

The equation $y=\frac{-x^2-6x+31}{8}$ represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula $d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$ , we find that the distance between (x, y) is

$\sqrt{(x+3)^2+(y-3)^2}$

and the distance between (x, y) and the directrix y = 7 is

$\sqrt{(y-7)^2}$ .

On the parabola, these distances are equal so, we solve for y:

$\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}$

6 0

3 years ago