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2 years ago

What is the degree of the polynomial T-4t^2+t^3

Mathematics

1 answer:

HACTEHA [7]2 years ago

5 0

Answer:

3 degrees.

Step-by-step explanation:

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Anyone want to help me with my math assignments ill post another question with the assignments on it

arlik [135]

whats the question?

787878787878

7 0

2 years ago

for his long distance phone service, lamar pays a $3 monthly fee plus 11 cents per minute. last month, lamar's long distance bil

e-lub [12.9K]

Let the number of minutes be = x.

Cost per minute = 11 cents = 0.11

Phone Bill = Monthly fee + 0.11* x

Substituting from the question

20.82 = 3 + 0.11x

3 + 0.11x = 20.82

0.11x = 20.82 - 3

0.11x = 17.82

x = 17.82/0.11

x = 162

<span>Lamar was billed for 162 minutes.</span>

4 0

3 years ago

Using 4 equal-width intervals, show that the trapezoidal rule is the average of the upper and lower sum estimates for the integr

prisoha [69]

Split up the interval [0, 2] into 4 subintervals, so that

$[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]$

Each subinterval has width $\dfrac{2-0}4=\dfrac12$ . The area of the trapezoid constructed on each subinterval is $\dfrac{f(x_i)+f(x_{i+1})}4$ , i.e. the average of the values of $x^2$ at both endpoints of the subinterval times 1/2 over each subinterval $[x_i,x_{i+1}]$ .

So,

$\displaystyle\int_0^2x^2\,\mathrm dx\approx\dfrac{0^2+\left(\frac12\right)^2}4+\dfrac{\left(\frac12\right)^2+1^2}4+\dfrac{1^2+\left(\frac32\right)^2}4+\dfrac{\left(\frac32\right)^2+2^2}4$

$=\displaystyle\sum_{i=1}^4\frac{\left(\frac{i-1}2\right)^2+\left(\frac i2\right)^2}4=\frac{11}4$

4 0

2 years ago

2 circles labeled Set A and Set B overlap. Set A contains 1, set B contains 3, and the overlap of the 2 circles contains 2. The

mezya [45]

The region(s) represent the intersection of Set A and Set B (A∩B) is region II

<h3>How to determine which region(s) represent the intersection of Set A and Set B (A∩B)?</h3>

The complete question is added as an attachment

The universal set is given as:

Set U

While the subsets are:

Set A
Set B

The intersection of set A and set B is the region that is common in set A and set B

From the attached figure, we have the region that is common in set A and set B to be region II

This means that

The intersection of set A and set B is the region II

Hence, the region(s) represent the intersection of Set A and Set B (A∩B) is region II