Given:
Sprayer and generator
1st Job: 6 hours each for a total of $90
2nd Job: 4 hours sprayer and 8 hours generator for a total of $100
Let x = spayer ; y = generator
6x + 6y = 90
4x + 8y = 100
6x = 90 - 6y
x = 90/6 - 6y/6
x = 15 - y
4x + 8y = 100
4(15-y) + 8y = 100
60 - 4y + 8y = 100
4y = 100 - 60
4y = 40
y = 40/4
y = 10
x = 15 - y
x = 15 - 10
x = 5
Sprayer = 5 per hour ; generator = 10 per hour
To check:
6x + 6y = 90
6(5) + 6(10) = 90
30 + 60 = 90
90 = 90
<span>4x + 8y = 100
</span>4(5) + 8(10) = 100
20 + 80 = 100
100 = 100
Answer:
h(x) = 11/(x -4)
Step-by-step explanation:
The domain of m(x) is restricted to x≠1. That means the domain of m(n(x)) must be restricted so that n(x)≠1, or x≠4.
The only offered choice with a domain restriction x≠4 is the 3rd choice:
h(x) = 11/(x -4)
Answer:
E
Step-by-step explanation:
let a, b, c represent the number of students in 6th, 7th, 8th grade
ratio of students : teachers = 28 : 1
There are 82 teachers , so 28 × 82 = 2296 students
Then
a + b + c = 2296 , that is
828 + b + c = 2296 ( subtract 828 from both sides )
b + c = 1468 → E
Here's a way to do it.
Let 4e +2 = 5n +1 . . . . . . for some integer n
Then e = (5n -1)/4 = n + (n -1)/4
We want (n-1)/4 to be an integer, so let it be integer m.
... m = (n -1)/4
... 4m = n -1
... 4m +1 = n
Substituting this into our expression for e gives
... e = (5(4m+1) -1)/4 = (20m +4)/4 = 5m +1
e = 5m+1 for any integer m
Answer:
ill help u lol im pretty positive its 8