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Mekhanik [1.2K]
4 years ago
12

Question Help

Mathematics
1 answer:
GREYUIT [131]4 years ago
8 0

Answer:

Step-by-step explanation:

A quadrilateral with one pair of parallel sides is a trapezoid.

If it has two pairs of parallel sides it is a parallelogram, but parallelograms are also trapezoids in the same way that dogs are also mammals.

A parallelogram has two pairs of congruent sides. (They may all be congruent, in which case it is a rhombus, but a rhombus is also a parallelogram in the same way that a poodle is also a dog). Therefore the shape you describe is not a parallelogram.

If the two nonparallel sides of a nonparallelogram trapezoid are congruent, it is called an isosceles trapezoid, otherwise "scalene". The shape you describe is a scalene trapezoid; this may be what you want.

However, technically it is still not quite there, because this terminology does not deal with the question of whether one of the nonparallel sides is congruent to one of the parallel sides. For instance, the trapezoid with vertices (0,0),(2,0),(1,2) and (0,2) is scalene but has congruent sides.

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Please help I am stuck. Would you also please explain on how to solve?
Bezzdna [24]

Answer:

<D is correct its confusing on the solving but

Step-by-step explanation:

4 0
3 years ago
Change a speed of 630 kilometres per hour to a speed in metres per second. Show your working
kupik [55]

Answer:

1750 m/s

Step-by-step explanation:

1km = 1000m

1 hour = 60 minutes = 3600 seconds

( 630 * 1000 )/ (60 * 60)

= 1750 m/s

5 0
3 years ago
what is the solution to the system of equations: x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10
ladessa [460]

Given equations are x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10 .

It seems you have missed to write = in the 2nd equation so i have fixed the sign and going to solve the following system of equations:

x-y-z=2 ...(i)

-x-3y-2z=4 ...(ii)

-x-2z=10 ...(iii)


solve (i) for x

x=2+y+z ...(iv)

plug (iv) into (ii)

-x-3y-2z=4

-(2+y+z)-3y-2z=4

-2-y-z-3y-2z=4

-2-4y-3z=4

-4y-3z=6...(v)


plug (iv) into (iii)

-x-2z=10

-(2+y+z)-2z=10

-2-y-z-2z=10

-2-y-3z=10

-y=12+3z

y=-12-3z...(vi)


plug (vi) into (v)

-4y-3z=6

-4(-12-3z)-3z=6

48+12z-3z=6

48+9z=6

9z=-42

z=-14/3


Now plug value of z into (vi)

y=-12-3z=-12-3(-14/3)=-12+14=2

y=2


plug value of y and z into (iv)

x=2+y+z=2+2-14/3=-2/3


Hence final answer is x=-2/3, y=2, z=-14/3

3 0
3 years ago
A physical education teacher plans to divide the seventh graders at Wilson middle school into teams of equal size for a year-end
serg [7]

Answer:

• It is possible to divide the seventh graders into teams of equal sizes.

,

• 13 students should be on each team.

Explanation:

The seventh grade of Wilson consists of three classes; one with 28 students, one with 29, and one with 34. Therefore, the total number of students in seventh grade is:

\text{Total}=28+29+34=91

He wants each team to have between 4 and 8 students.

\begin{gathered} \frac{91}{4}\approx22.75 \\ \frac{91}{5}\approx18.2 \\ \frac{91}{6}\approx15.2 \\ \frac{91}{7}\approx13 \\ \frac{91}{8}\approx11.4 \end{gathered}

Therefore:

• It is possible to divide the seventh graders into teams of equal sizes.

,

• 13 students should be on each team.

8 0
1 year ago
HELP ASAP WILL GIVE OUT BRAINLIEST!
8090 [49]
It is the first one for sure! Hope this helps
6 0
3 years ago
Read 2 more answers
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