So what I did was I wrote down the problem 50 - 10x = 20.
The first step I did was take 50 and subtract it from both sides: 50 - 10x = 20
-50 -50
After that i cross out the so 50's and take 20 and subtract it to 50 which gave me -30. So when you write this down you rewrite it as: -10x = -30
Last step: take the -10 and divide it by both sides the cross out the two -10's cause it's going to be written as -30/-10 which would give you x = 3. So there is your answer, hope this helps. :)
~Shadow
Here's the equation:
5 + x=39
-5 -5
Here's the answer: x=34
Construct the perpendicular bisector of ST
Answer:
Factors are (x-1), (x+1), and (x+2).
Step-by-step explanation:

Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC =
= 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C