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Nastasia [14]
3 years ago
5

Please help me and hurry

Mathematics
1 answer:
Darya [45]3 years ago
8 0

A and b equal each other

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Given the conditional statement, match the following.
Step2247 [10]

Hypothesis (p): A polygon is a square

Conclusion: (q): It is a rectangle

Inverse: q → p         <em>If a polygon is a rectangle, then it is a square</em>

Converse: ~p → ~q        <em>If a polygon is not a square, then it is not a rectangle.</em>

Contrapositive: ~q → ~p    <em>If a polygon is not a rectangle, then it is not a square</em>

Your answers are correct

5 0
3 years ago
What multiplication problem is equivalent to 3 3/8 divide by 3/8
Anni [7]

The expression 3\frac{3}{8}\div \frac{3}{8} can be written in multiplication problem as: 3\frac{3}{8}\times \frac{8}{3} or \frac{27}{8}\times \frac{8}{3}

Step-by-step explanation:

We need to find What multiplication problem is equivalent to 3\frac{3}{8}\div \frac{3}{8}

We are given: 3\frac{3}{8}\div \frac{3}{8}

Writing it in multiplication problem.

When division sign is changed to multiplication sign, the fraction is reciprocated.

3\frac{3}{8}\div \frac{3}{8}

Converting division into multiplication

3\frac{3}{8}\times \frac{8}{3}

or we can write as:

\frac{27}{8}\times \frac{8}{3}

So, the expression 3\frac{3}{8}\div \frac{3}{8} can be written in multiplication problem as: 3\frac{3}{8}\times \frac{8}{3} or \frac{27}{8}\times \frac{8}{3}

Keywords: Solving Fractions

Learn more about Solving Fractions at:

  • brainly.com/question/2456302
  • brainly.com/question/4390083
  • brainly.com/question/2456302

#learnwithBrainly

4 0
3 years ago
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
The sun will eventually become a
astra-53 [7]
Blackhole or supernova because of its mass.
3 0
3 years ago
Read 2 more answers
Is 800 divisible by 5?<br> yes<br> no<br> Submit
Ilia_Sergeevich [38]

Answer: yes(800/5=160)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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