Please help me and hurry

Given the conditional statement, match the following.

Step2247 [10]

Hypothesis (p): A polygon is a square

Conclusion: (q): It is a rectangle

Inverse: q → p If a polygon is a rectangle, then it is a square

Converse: ~p → ~q If a polygon is not a square, then it is not a rectangle.

Contrapositive: ~q → ~p If a polygon is not a rectangle, then it is not a square

Your answers are correct

5 0

3 years ago

What multiplication problem is equivalent to 3 3/8 divide by 3/8

Anni [7]

The expression $3\frac{3}{8}\div \frac{3}{8}$ can be written in multiplication problem as: $3\frac{3}{8}\times \frac{8}{3}$ or $\frac{27}{8}\times \frac{8}{3}$

Step-by-step explanation:

We need to find What multiplication problem is equivalent to $3\frac{3}{8}\div \frac{3}{8}$

We are given: $3\frac{3}{8}\div \frac{3}{8}$

Writing it in multiplication problem.

When division sign is changed to multiplication sign, the fraction is reciprocated.

$3\frac{3}{8}\div \frac{3}{8}$

Converting division into multiplication

$3\frac{3}{8}\times \frac{8}{3}$

or we can write as:

$\frac{27}{8}\times \frac{8}{3}$

So, the expression $3\frac{3}{8}\div \frac{3}{8}$ can be written in multiplication problem as: $3\frac{3}{8}\times \frac{8}{3}$ or $\frac{27}{8}\times \frac{8}{3}$

Keywords: Solving Fractions

Learn more about Solving Fractions at:

#learnwithBrainly

4 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

The sun will eventually become a

astra-53 [7]

Blackhole or supernova because of its mass.

3 0

3 years ago

Read 2 more answers

Is 800 divisible by 5? yes no Submit

Ilia_Sergeevich [38]

Answer: yes(800/5=160)

Step-by-step explanation: