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2 years ago

1 + 1 I'm confusedddddddddddddddddddddddddddddddddddddddddd

Mathematics

1 answer:

Flura [38]2 years ago

8 0

Answer:

its 2 homie

Step-by-step explanation:

1+1 equals 2 one thing plus another equals the next number.

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If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V, the current flowing through the circ

Lena [83]

Option C

Answer:

The current flowing through the circuit is 5 A

Solution:

Given that resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V.

We have to find the current flowing through the circuit.

By Ohms law, the relation between the resistance, voltage and current in the circuit is given as,

$\bold{V=I \times R}$ ---- eqn 1

where, V = voltage in the circuit

I = current flowing through the circuit

R = resistance of the electric circuit

From question given that, R = 12 ohms; V = 60 V

By using eqn 1, the current flowing through the circuit is given as

$60 = I \times 12$

$I = \frac{60}{12} = 5$

Hence the current flowing through the circuit is 5A.

8 0

2 years ago

A recipe that serves four people calls for 2 1/4 cups of butter. How many cups of butter needed to serve 10 people? Show your wo

Eduardwww [97]

Answer:

5 5/8

Step-by-step explanation:

2 1/4 * 2 = 4 1/2

2 1/4 / 2 = 1 1/8

4 4/8 + 1 1/8 = 5 5/8

7 0

2 years ago

WILL GIVE BRAINIEST ANSWER IF ANSWER IS CORRECT

IRISSAK [1]

F(x) = x+4
f(4) = 8, f(5) = 9
Change = 1

f(x) = 3x-7
f(-3) = -16, f(5) = 8
Change = 24/8 = 3

f(x) = 9x+1
f(-5) = -44, f(-2) = -17
Change = 27/3 = 9

f(x) = 2x+9
f(1) = 11, f(2) = 13
Change = 2

In order: f(x) = 9x+1, f(x) = 3x-7, f(x) = 2x+9, f(x) = x+4

4 0

2 years ago

Read 2 more answers

NEED ASAP WILL GIVE BRAINLIEST Write a real world problem that can be represented by the following inequality, 15X - 20 ≤ 130 ,a

ddd [48]

Answer:

I used my name, lol

Step-by-step explanation:

Kat wants to use her money to support animals at a shelter after receiving her pay check from work . She pays $15 per animal, and leaves $20 for the workers. She can spend at most $130. How many animals can she help?

Solve for x

$15x-20\leq 130$

Add 20 to both sides to isolate x

$15x-20+20\leq 130+20\\15x\leq 150$

Divide each side by 15

$\frac{15x}{15}\leq \frac{150}{15} \\\\x\leq 10$

Kat can help at most 10 animals.

(I am so sorry I took so long, I couldn't come up with anything.)

5 0

3 years ago

Find the area of a triangle bounded by the y-axis, the line f(x)=9−4/7x, and the line perpendicular to f(x) that passes through

Setler79 [48]

ANSWER:

The area of the triangle bounded by the y-axis is $\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

SOLUTION:

Given, $f(x)=9-\frac{-4}{7} x$

Consider f(x) = y. Hence we get

$f(x)=9-\frac{-4}{7} x$ --- eqn 1

$y=9-\frac{4}{7} x$

On rewriting the terms we get

4x + 7y – 63 = 0

As the triangle is bounded by two perpendicular lines, it is an right angle triangle with y-axis as hypotenuse.

Area of right angle triangle = $\frac{1}{ab}$ where a, b are lengths of sides other than hypotenuse.

So, we need find length of f(x) and its perpendicular line.

First let us find perpendicular line equation.

Slope of f(x) = $\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-4}{7}$

So, slope of perpendicular line = $\frac{-1}{\text {slope of } f(x)}=\frac{7}{4}$

Perpendicular line is passing through origin(0,0).So by using point slope formula,

$y-y_{1}=m\left(x-x_{1}\right)$

Where m is the slope and $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)$

$y-0=\frac{7}{4}(x-0)$

$y=\frac{7}{4} x$ --- eqn 2

4y = 7x

7x – 4y = 0

now, let us find the vertices of triangle, one of them is origin, second one is point of intersection of y-axis and f(x)

for points on y-axis x will be zero, to get y value, put x =0 int f(x)

0 + 7y – 63 = 0

7y = 63

y = 9

Hence, the point of intersection is (0, 9)

Third vertex is point of intersection of f(x) and its perpendicular line.

So, solve (1) and (2)

$\begin{array}{l}{9-\frac{4}{7} x=\frac{7}{4} x} \\\\ {9 \times 4-\frac{4 \times 4}{7} x=7 x} \\\\ {36 \times 7-16 x=7 \times 7 x} \\\\ {252-16 x=49 x} \\\\ {49 x+16 x=252} \\\\ {65 x=252} \\\\ {x=\frac{252}{65}}\end{array}$

Put x value in (2)

$\begin{array}{l}{y=\frac{7}{4} \times \frac{252}{65}} \\\\ {y=\frac{441}{65}}\end{array}$

So, the point of intersection is $\left(\frac{252}{65}, \frac{441}{65}\right)$

Length of f(x) is distance between $\left(\frac{252}{65}, \frac{441}{65}\right)$ and (0,9)

$\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(9-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+0} \\ &=\frac{252}{65} \end{aligned}$

Now, length of perpendicular of f(x) is distance between $\left(\frac{252}{65}, \frac{441}{65}\right) \text { and }(0,0)$

$\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(0-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+\left(\frac{441}{65}\right)^{2}} \\ &=\frac{\sqrt{(12 \times 21)^{2}+(21 \times 21)^{2}}}{65} \\ &=\frac{63}{65} \sqrt{65} \end{aligned}$

Now, area of right angle triangle = $\frac{1}{2} \times \frac{252}{65} \times \frac{63}{65} \sqrt{65}$

$=\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

Hence, the area of the triangle is $\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

8 0

3 years ago