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4 years ago

10% of what number is 14

2 answers:

7 0

The answer is 140

basically, just multiply it by 10

or if you want the longer version,

1/10x = 14
10[1/10x] = 10[14]
x= 140

vovikov84 [41]4 years ago

3 0

That would be 140

10% is basically the same thing as 1/10. So if you want to find the answer, do the opposite of 1/10, which is 10.

That way, you can get 14 * 10 = 140

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Have a go at this one!

Sonbull [250]

Answer:

I THINK 96

Step-by-step explanation:

11x11=121

5x5=25

121-25=96

7 0

3 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

3 years ago

Find the limit of the function algebraically. limit as x approaches negative nine of quantity x squared minus eighty one divided

scoray [572]

Let me express the equation clearly:

lim x→-9 (x²-81)/(x+9)

Initially, we solve this by substituting x=-9 to the equation.

((-9)²-81)/(-9+9) = 0/0

The term 0/0 is undefined. This means that the solution is not see on the number line because it is imaginary. Other undefined terms are N/0 (where N is any number), 0⁰, 0×∞, ∞-∞, 1^∞ and ∞/∞. One way to solve this is by applying L'Hopitals Rule. This can be done by differentiating the numerator and denominator of the fraction independently. Then, you can already substitute the x=-9.

(2x-0)/(1+0) = 2x = 2(-9) = -18

The other easy way is to substitute x=-8.999 to the original equation. Note that the term x→-9 means that x only approaches to -9. Thus, you substitute a number that is very close to -9. Substituting x=-8.999

((-8.999)²-81)/(-8.999+9) = -18

7 0

3 years ago

Tell whether the angles are adjacent or vertical. Then find the value of x.

Nimfa-mama [501]

Answer:

adjacent, x=15

Step-by-step explanation:

the angels are connected so they are adjacent, the red box shows that it is a 90 degree angle so adding both angels together means 90=6x so x=15

8 0

3 years ago

Need help on this please this one is hard for me

pshichka [43]

9514 1404 393

Answer:

y = -7x

Step-by-step explanation:

The line goes through the origin, so the y-intercept is b=0.

The line goes through the point (1, -7), so has a "rise" of -7 for a "run" of 1. The slope is ...

m = rise/run = -7/1 = -7

Then the slope-intercept form equation is ...

y = mx + b

y = -7x

6 0

3 years ago