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3 years ago

Find the least common multiple of 10 and 16.

Mathematics

2 answers:

hammer [34]3 years ago

7 0

I'm pretty sure its 80, if this isnt for school i suggest Calculator Soup's LCM calculator (:

Dafna11 [192]3 years ago

3 0

The least common multiple of 10 and 16 is 80

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Niko got the jumbo ice cream cone at the Dutchess County Fair. The amount of ice cream can be modeled using a cone whose height

motikmotik

85 over 320 of a cup

6 0

3 years ago

Read 2 more answers

Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans

tatyana61 [14]

Answer:

3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

$\dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}$

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

$\dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}$

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0

3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!

castortr0y [4]

Answer:

$3.75

Step-by-step explanation:

dimes= x

quarters= x+2

nickels= 2x+2

sum is 3.75

.10x+.25(x+2)+0.05(2x+2)=3.75

.10x+.25x+.50+0.10x+0.10=3.75

0.45x=3.15

x=7 dimes (0.70)

x+2=9 quarters (2.25)

2x+2=16 nickels (0.80)

They add to $3.75

5 0

3 years ago

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A group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students

ValentinkaMS [17]

Answer:

A maximum of 43 students and 11 teachers can go to the trip.

Step-by-step explanation:

Since a group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students, and the bus can hold a maximum of 54 teachers and students, to determine the possible numbers of teachers and students who can go on the trip, the following calculation must be performed:

4 + 1 = 5

54/5 = X

10.8 = X

10 x 4 = 40

10 x 1 = 10

4 - 1 = 3

Therefore, a maximum of 43 students and 11 teachers can go to the trip.

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3 years ago

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