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GenaCL600 [577]
3 years ago
13

Alex sold wrapping paper rolls (r) as part of a school fundraiser. He earned a total of 165 reward points from his sales. Using

the equation 2.5r = 165, how many rolls of wrapping paper did Alex sell?
Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0
He sold 66 wrapping paper because all you want to do is divide
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After the translation, where is A located?
vovikov84 [41]

Answer:

(-3, 13)

Step-by-step explanation:

The transformation that moves a point 4 left and 8 up is ...

 (x, y) ⇒ (x -4, y +8)

The transformation that reflects a point across the y-axis is ...

 (x, y) ⇒ (-x, y)

Applied after the translation, the transformation of ∆ABC becomes ...

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Then point A gets moved to ...

 A(7, 5) ⇒ A'(4 -7, 5 +8) = (-3, 13)

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3 years ago
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3 years ago
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Determine the range of <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28x-5%29%28x%2B3%29%7D" id="TexFormula1" title="\sqrt{(x-5)(
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Consider the function f(x) = (x-5)(x+3). It is a parabola with a vertex below the x-axis and x-intercepts of 5 and -3. The vertex x-coordinate is in the middle of the two x-intercepts, so the vertex x-coordinate is (5+-3)/2 = 1. The y-coordinate of the vertex is obtained by substituiting the x-coordinate of the vettex inside, which gets you -16. Its vertex is at (1,-16) and it opens upward; therefore, (x-5)(x+3) gets you a range of y \ge -16.

But when you take square root,  there are no negatives. Anything where the range is negative in (x-5)(x+3) is cut out, and we are left with y \ge 0. Therefore, the range of \sqrt{(x-5)(x+3)} is y \ge 0

4 0
3 years ago
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