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sweet-ann [11.9K]
3 years ago
14

Evaluate 2^-4 pleaseee help asap

Mathematics
2 answers:
Alexxandr [17]3 years ago
5 0

Answer:

1/16

Step-by-step explanation:

2^-4

We know that a^ -b = 1/ a^b

2^-4 = 1/2^4

2^4 =16

so 1/2^4 = 1/16

vichka [17]3 years ago
3 0

Answer:

2 ^-4 = 1/16

Step-by-step explanation:

2^-4 = 1/2^4

2^4 =16

so 1/2^4 = 1/16

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How many 0.75 pound packages can you make with 6 pounds of sunflower seeds?
madreJ [45]
If you have 6 pounds of sunflower seeds and make 0.75 packages, 6/0.75 is 8 so you can make eight .75 packages with 6 pounds
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3 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
4 years ago
Helpppp know!!!! It’s math and it is genmontry
vladimir2022 [97]

Answer:

Part 7) Adjacent angles

m<SUR and m<RUN

m<TUP and m<PUQ

Part 8) Vertical acute angles

m<SUR and m<PUQ

m<RUN and m<TUP

Part 9) Supplementary angles

m<SUT and m<TUQ

m<SUR and m<QUR

Part 10) m

Part 11) m<RUQ is greater than m< TUR

Part 12) x=21\°

Part 13) m

Step-by-step explanation:

Part 7) we know that

we know that

Two angles are Adjacent when they have a common side and a common vertex

In this problem

m<SUR and m<RUN ----> are adjacent angles

because have a common side UR and a common vertex U

m<TUP and m<PUQ ----> are adjacent angles

because have a common side UP and a common vertex U

Part 8) we know that

An angle is acute when is measure is less than 90 degrees

Vertical Angles are the pair of congruent angles opposite each other when two lines cross

In this problem

m ------> by vertical angles

m ------> by vertical angles

Part 9) we know that

Two angles are supplementary if its sum is equal to 180 degrees

In this problem

m ------> by supplementary angles

m ------> by supplementary angles

Part 10) Find m<QUR

we know that

m ------> by supplementary angles

we have

m

substitute

41\°+m

m

Part 11) which is greater m<TUR or m< RUQ

we know that

m<TUR=m<TUS+m<SUR

substitute the values

m

m ----> see the procedure problem 10

therefore

m<RUQ is greater than m< TUR

Part 12) Find the measure angle x

4x=84\° ------> by vertical angles

solve for x

x=84\°/4=21\°

Part 13) m<KMH

we know that

m -----> by supplementary angles

m

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irga5000 [103]
The product would be 432x^2y^3. 
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A circle has a diameter of 4 meters. What is the best approximation of its area? Use 3.14 to approximate for π . 6.28 m² 12.56 m
hram777 [196]
 i would go with 12.56

7 0
4 years ago
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