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3 years ago

tony had 1 1/2 gallons of orange juice. He drank 2/7 of the orange juice he had. How mucj orange juice did Tony drink?

1 answer:

6 0

There are several information's of immense importance already given in the question.
Amount of juice that Tony actually had = 11/2 gallons
Amount of juice that Tony drank = (11/2) * (2/7) gallons
= 11/7 gallons
From the above deduction, we can easily conclude that the amount of juice that Tony drank was 11/7 gallons.

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Solve for x 2x/3 +1 =3

Bess [88]

Answer:

x=3

Step-by-step explanation:

Hello,

The first thing you do is set up your equation, and we are solving for x so we are going to get x by itself on one side of the = sign.

2x/3+1=3 First thing: subtract 1 from BOTH sides.

-1 -1

----------------------

2x/3=2 Multipliy by 3 on both sides

*3 *3

-----------------------

2x=6 Divide by 2 on both sides

/2 /2

-----------------------

x=3

I hope this helped you!!!

5 0

3 years ago

I’m gonna lose the New York and take a plane to Lisbon. When Amanda left the house it was -8°. When the plane landed in the spin

11111nata11111 [884]

Answer:

Step-by-step explanation:

Given:

-8

+20°

Solution:

-8+20 = 12

Therefore the answer is 12

3 0

2 years ago

Even more trig ratios see attachment

egoroff_w [7]

Step-by-step explanation:

1. Use the Pythagorean theorem to solve for side KM:

16^2+KM^2=34^2
256+KM^2=1156
KM^2=900
KM=30

2. Cosine is adjacent over hypotenuse, so cosine of M would be KM/34, or 30/34

3. Tangent is opposite over adjacent, so tangent of L will be KM/16, or 30/16

4. Sine is opposite over hypotenuse, so sine of M will be 16/34

5. KM=30, solved for in step 1.

hope this helps!!

4 0

3 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$