We have been given a quadratic function 
and we need to restrict the domain such that it becomes a one to one function.
We know that vertex of this quadratic function occurs at (5,2).
Further, we know that range of this function is 
.
If we restrict the domain of this function to either ![(-\infty,5]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C5%5D)
or 
, it will become one to one function.
Let us know find its inverse.
Upon interchanging x and y, we get:
Let us now solve this function for y.
Hence, the inverse function would be 
if we restrict the domain of original function to and the inverse function would be 
if we restrict the domain to .
Answer:
Tn=a + (n-1)d
a= first term = 14
n= This is the term you're looking for... In this case... That's the 73rd term
d=Common difference (since its an AP)
d= second term - first term -- Or 3rd term - 2nd term = 23-14
d=9
T = 14 + (73-1)9
T= 14 + (72)9
T= 14 + 648
T=662.
Answer:
x=3 is the number
Step-by-step explanation:
Suppose number be "x".
Equation will be
7x + x = 24
8x = 24
x = 24/8
x = 3
Answer:
Step-by-step explanation:
3) Sin30 = 11/x
x = 11/Sin30 = 11/0.5
x = 22
Tan 30 = 11/y
y = 11/tan30 = 11/0.5774
y = 19.1
4) Sin30 = 6/x
x = 6/Sin30 = 6/0.5
x = 12
Tan 30 = 6/y
y = 6/tan30 = 6/0.5774
y = 10.39
5) Sin45 = 9√2/y
y = 9√2/Sin45 = 9√2/(√2/2) =
9√2 × 2/√2 = 18
x = 18
Tan 45 = 9√2/x
x = 9√2/Tan 45 = 9√2/1
x = 9√2
6)
Sin60 = 9/x
x = 9/Sin60 = 9/0.866
x = 10.39
Tan 60 = 9/y/2 = 18/y
1.7321 = 18/y
y = 18/1.7321
y = 10.39
