1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dominik [7]
2 years ago
5

A) 6, 8, 12, 20, 36, 68,?

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

numbers

Step-by-step explanation:

You might be interested in
A 1,600.00 principal earns 7% interest compounded semiannually twice per year' after 33 years what is the balance in the account
Dmitrij [34]
A=1600(1+0.07/2)^(2*33)=15,494.7
7 0
3 years ago
Hi! can someone please help? i added a pic so that u can see what i need help on. hopefully it helps
almond37 [142]

Answer:

I'm pretty sure that the answers would go, Wrong, increased, 9 1/2 points, 6 5/8 points, dropped, 12 3/4 points.

Step-by-step explanation:

The reason why it would be wrong is because the amount of points lost was less than the total amount of points gained.

In week one and two the company gained 9 1/2 points and 6 5/8 points. When you add them together, you get 16 1/8 points.

In week three the company lost 12 3/4 points. If you multiply the fraction to change the denominator to 8, the mixed fraction becomes 12 6/8.

16 1/8 - 12 6/8 = 3 3/8

As you can see, there are still points left over.

In the fourth week, they ended up losing all of their points and then some more, but from my understanding it's just asking about the third week.

Hope that this helps!

4 0
2 years ago
60:92=105:n what is n?
PIT_PIT [208]
Hey! I'll provide you the answers!

First you want to simplify the equation using cross-multiplication.

15n = 2415

Finally, you would want to divide both sides by 15.

n = 161
5 0
3 years ago
Read 2 more answers
For the scenarios presented in Problems 9–17, identify a problem worth studying and list the variables that affect the behavior
Nastasia [14]

Answer:

Problem: A company with a fleet of trucks faces increasing maintenance costs as the age and mileage of the trucks increase

Identify a problem worth studying : Yes, this problem is worth studying as it illustrate the classical optimization problem where to either minimize or maximize the outcome given some constraints. In this problem we need to maximize our profit by minimizing our maintenance cost give the age of trucks.

List the variables that affect the behavior you have identified: Lease expense, license, taxes, insurance, number of trucks, number of mechanics, type of fuel, maintenance and repair, labor, number of breakdowns, wait time to repair, loss of revenue and delay penalties, drivers retention and attrition, and number of customer reviews (negative and positive) the service.

Which variables would be neglected completely: Unless there are plans to relocate to different state with different regulations, the following variables can neglected completely: Lease expense, licenses and permits, taxes, insurance, number of trucks, number of mechanics, type of fuel.

Which might be considered as constants initially: Assuming that our mechanics are full time employees, the labor cost can be considered constant. However, the parts and materials associated with the labor are not constant. And any one time cosmetic fixes can be considered constants such as a small paint job or seat cleaning.

Can you identify any sub models you would want to study in detail?: The sub model that I want to study in more detail is as follow:

Truck ownership cost=truck depreciation+truck Return on Investment (ROI)

As the truck depreciation is constant, the main focus will be on truck Return on Investment (ROI).

Truck Return on Investment (ROI)=(the gain from the truck−Cost of investment)/cost of investment.

Hence the detailed subsystem can be as follow:

Cost of investment=(Fuel cost +maintenance cost +breakdown cost+wait cost).

Identify any data you would want collected:  The data you would want collected is maintenance cost and type of maintenance and specifically the tracks and truck parts that break down the most. The wait time needed to fix and maintain the trucks. And finally customer reviews. In other words, I would collect any data that directly or indirectly impact revenues. With the collected data, I would well informed about the best time to decide replacing trucks that are performing very poorly and negatively impacting the bottom-line of the company.

Step-by-step explanation:

The specific problem is selected above and it is worth analyzing and studying because is is similar to a classical optimization problem. This is because the desired output can be either maximized or minimized by adjusting the values of certain constraints such as maintenance cost, trucks parts and other necessary parameters.

8 0
2 years ago
Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.
finlep [7]

Answer:

a) v = \frac{[L]}{[T]} = LT^{-1}

b) a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

c) \int v dt = s(t) = [L]=L

d) \int a dt = v(t) = [L][T]^{-1}=LT^{-1}

e) \frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

v = \frac{ds}{dt}

a= \frac{dv}{dt}

Part a

If we do the dimensional analysis for v we got:

v = \frac{[L]}{[T]} = LT^{-1}

Part b

For the acceleration we can use the result obtained from part a and we got:

a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

Part c

From definition if we do the integral of the velocity respect to t we got the position:

\int v dt = s(t)

And the dimensional analysis for the position is:

\int v dt = s(t) = [L]=L

Part d

The integral for the acceleration respect to the time is the velocity:

\int a dt = v(t)

And the dimensional analysis for the position is:

\int a dt = v(t) = [L][T]^{-1}=LT^{-1}

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

7 0
3 years ago
Other questions:
  • Solve 5(x+9) - 4 = 71 for x
    9·2 answers
  • you spend 10 mind doing homework then u spend 2 hours watching television as a fraction in simplest form
    8·1 answer
  • I need to know what y is equal to. <br> 3/4 = 5/6 + y
    11·2 answers
  • Solve the equation by factoring and applying the zero product property.
    14·2 answers
  • An arts academy requires there to be 5 teachers for every 90 students and 3 tutors for every 30 students. How many students does
    8·1 answer
  • Parallelogram CDEF with vertices C(-4,-4), D(-2, 0), E(6, 1), and F(4, -3) in the line y = 2.
    14·1 answer
  • Find the measure of the indicated angle to the nearest degree.
    9·1 answer
  • Someone please help!!! This is due tonight!! I’ll give brainliest
    7·2 answers
  • Omg I do not understand this
    6·2 answers
  • Amelia has $25 to spend on makeup this week she loves lipstick each lipstick tube cost $4 what is the maximum number of lipstick
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!