Answer:
FE = 30°
Step-by-step explanation:
arc FGC = arc FG + arc GB + arc BC
220° = 90° + arc GB + 70° . . substitute known values
60° = arc GB . . . . . . . . . . . . . subtract 160°
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External angle A is half the difference of arcs EG and GB:
30° = (1/2)(arc FE +90° -60°) . . . substitute known values
60° = arc FE + 30° . . . . . . . . . . . multiply by 2 and simplify
30° = arc FE . . . . . . subtract 30°
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The key to this problem is the relationship between external angle A and the measures of the arcs it subtends.
<span>the sum of 5 and 2x : 5 + 2x
You can't add this because they are not like terms
</span>
Answer:
5,18,12 cms are the answer.
Step-by-step explanation:
Given is a triangle ABC. Point D is the centroid.
E,F and G are midpoints of CB, BA and AC respectively.
AE, BF and CG are medians of the triangle.
We know that centroid divides the median in the ratio 2:1
Using this we find that AD:DE = 2:1
Or AD+DE:DE = (2+1):1
AE:DE =3:1
15:DE = 3:1 . Hence DE =5 cm.
On the similar grounds we find that DF = 1/3 BF = 9
Hence BD = DF-BF = 27-9 =18 cm
and also
CG = 3/2 times CD = 12 cm.
Problem One
Find AM
AM = 71.5 - 22 = 49.5
Step Two
State the Givens.
AM = 49.5
MN = 71.5
MB = x
MP = 97.5
Step Three
Set up the Proportion
AM : NM :: x : PM
49.5 : 71.5 :: x : 97.5
Substitute and solve
49.5 / 71.5 = x / 97.5 Cross Multiply
49.5 * 97.5 = 71.5 * x Combine the numbers on the left.
4860.375 = 71.5 * x Divide by 71.5
4860.375 / 71.5 = x
x = 67.98
Problem Two
Remark
This is just a straight application of the Pythagorean Theorem
a^2 + b^2 = c^2
a = 10
b = 24
c = ??
10^2 + 24^2 = c^2
100 + 576 = c^2
676 = c^2
sqrt(c^2) = sqrt(676)
c = 26 <<<< answer
