If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper
Answer: We are given there are 49 cars
Also these 49 cars are in a line stretched 528 feet.
Now the average length of the car is:
Average length = 
=
Therefore, the average length of car is 10.78 feet
If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.
now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.
Answer:
(6, -2)
Step-by-step explanation:
The midpoint of the segment RS is point M (5, 3). Therefore, the average of the x coordinates of R and S is 5, and the average of the y coordinates of R and S is 3. The x coordinate of R is 4. For 4 and the x coordinate of S to have an average of 5, the x coordinate of S must be 6. Therefore, our point is of the form (6, y). For 8 and the y coordinate of S to have an average of 3, the y coordinate of S must be -2. Therefore, our answer is (6, -2)
Answer:
EH = 10
Step-by-step explanation:
Because F is a midpoint, that means that FG and EF are congruent to each other. So, since FG = 2, that means that EF also equals 2. Because FH also includes FG, you can take the 2 from the FG, and then take that 2 away from 8. Now you know that GH = 6. All that is left is to add all 3 of the units together (2+2+6=10).
