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3 years ago

What is the area of this figure?

Mathematics

1 answer:

Paraphin [41]3 years ago

6 0

Area of square
= 7x7
=49
Area of triangle
=0.5x 7x12
=42
Total area of figure
=49+42
=91

Hence, answer is D

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X = 5 -3 x is not quadratic what is the reason

OleMash [197]

Answer:Although the Quadratic Formula always works as a strategy to solve quadratic equations, for many problems it is not the most efficient method. Sometimes it is faster to factor or complete the square or even just "out-think" the problem. For each equation below, choose the method you think is most efficient to solve the equation and explain your reason. Note that you do not actually need to solve the equation. a. x2+7x−8=0x

+7x−8=0, b. (x+2)2=49(x+2)

=49, c. 5x2−x−7=05x

−x−7=0, d. x2+4x=−1x

+4x=−1.

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3 years ago

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ANGLE KLM and ANGLE RST are supplementary angles. If ANGLE KLM is (7x) and ANGLE RST is (36-x) what is the value of x ? Please h

liberstina [14]

Answer:

Step-by-step explanation:

Angle B measures 60°. What is the measure of the angle that is complementary to angle B?

30°

60°

120180°

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2 years ago

What is the slope of the line 3y=4x+5? Answer choices: A. 5/3 B. 4/3 C. 2 D.4

yawa3891 [41]

Answer:

B. 4/3

Step-by-step explanation:

slope-intercept formula is y=mx+b, where m is the slope and y has to be by itself.

dividing 4 by 3 cant be more simplified than 4/3.

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3 years ago

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Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did

vladimir1956 [14]

Mukat gets 40, Usha gets 8

Step-by-step explanation:

Mukat = 5 × Usha

After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)

Then Mukat = final number of books for Usha

5 × Usha - 16 = Usha + 16

(5 × Usha ) - Usha = 16+16

4 × Usha = 32

Usha = 8 i.e her number of books.

Mukat = 5×8=40.

I HOPE IT'S OK

6 0

3 years ago

Hat is the solution to the equation 3/3(4c + 16)=2c+9 ? c =

marusya05 [52]

If it is $\frac{3}{3(4c+16)}$ =2c+9, go to AAAAAA
if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, go to BBBBB

AAAAAAAAA
$\frac{3}{3(4c+16)}$ =2c+9
$\frac{1}{4c+16}$ =2c+9
times 4c+16 to both sides
1=(2c+9)(4c+16)
distribute
1=8c^2+68c+144
minus 1 both sides
0=8c^2+68c+143
use quadratic formula
c= $\frac{-17- \sqrt{3} }{4}$ or $\frac{-17+ \sqrt{3} }{4}$

BBBBBBBBBBBB
(3/3)(4c+16)=2c+9
1(4c+16)=2c+9
4c+16=2c+9
minus 2c both sides
2c+16=9
minus 16 both sides
2c=-7
divide both sides by 2
c=-7/2
c=-3.5

if it is $\frac{3}{3(4c+16)}$ =2c+9,
c= $\frac{-17- \sqrt{3} }{4}$ or $\frac{-17+ \sqrt{3} }{4}$

if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, c=-3.5

7 0

3 years ago

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