Answer:
Given that JN was bisected, JL ≅ LN
Given that KM was bisected, KL ≅ ML
∠JLK ≅ ∠MLN because of vertical angles.
∠JLK is contained by JL and KL.
∠MLN is contained by ML and LN.
Therefore ΔJKL ≅ ΔNML by the SAS postulate.
Step-by-step explanation:
The SAS postulate states that when you know two triangles have an equal angle, and that angle is formed by two sides that are equal in both triangles, the two triangles are congruent.
When a line is bisected, it means it was cut in two equal parts.
Since two lines were bisected and each form a side in the triangles, two sides are congruent.
The contained angles, ∠JLK and ∠MLN, are equal because of vertical angles. Vertical angles occur when two straight lines intersect. Angles that are opposite to each other are equal in all cases.
Answer:
no
Step-by-step explanation:
Answer:
B, the one with the line and shaded the top on the right side. (The one that goes to 7 on the x axis).
Step-by-step explanation:
First I find which graph as y -intercept of -3, which is all of them.
Next, I find with graph has a slope of 1/3. (rise 1 run 3). Only B and D has a slope of 1/3 (The ones that has a less steep graph. )
Then, I use the coordinate (0,0) to see which side the graph shades. I plug it into the inequality. (0)≥1/3(0)-3. Solve. Is 0 greater than -3. YES! so we shade the part where (0,0) is shaded which is B.
no thanks but I'll see if I can get friends to join
