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scoundrel [369]
3 years ago
9

According to the 1993 World Almanac, the number of calories a person walking at 3 mph burns per minute depends on the persons we

ight as in the following table
Weight (pounds) 100 120 150 170 200 220
Walking (cal) 2.7 3.2 4.0 4.6 5.4 5.9

(a) On a sheet of paper, graph the linear function for the calories used per minute whle walking, as a function of weight, w. Find an approximate formula for this equation.

(b) Domain and range?

The main problem i have is the formula and range. Help please and thank you!
Mathematics
1 answer:
zaharov [31]3 years ago
3 0
150 pounds is your answer
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3 more than one-half of a number is 10. What is the number?
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Answer:

14

Step-by-step explanation:

Let's call the number x.

\dfrac{x}{2}+3=10

Subtract 3 from both sides:

\dfrac{x}{2}=7

Multiply both sides by 2:

x=14

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Emma bought a carpet for $40. Later that carpet was marked down by 20%. By how much has the value been decreased?​
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Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
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Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
Solve for x. ax-bx=k​
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Answer:

x= k/a-b

Step-by-step explanation:

Move all terms to the left side and set equal to zero as well as each factor.

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