Answer:
that is not a function because for one value of x you get two different values of y. it is circle (x+3)^2+(y-3)^2=9. but if you divide it in two half circles (upper and lower) than you have two functions y=3+sqrt(-x^2-6x) and y=3-sqrt(-x^2-6x)
domain is x ∈ [-6,0] and range y ∈ [0,3] for one and for other y ∈ [3,6]
Answer:
The answer is No.
<em>example: 495/9=55</em>
Step-by-step explanation:
No, the quotients does not always have the same number of digits when dividing 3-digit numbers by 1-digit numbers.
since let us consider a three digit number as: 495
on dividing this number by a single digit number i.e. 9 we get the quotient as 55; which is not a three digit number.
i.e. 495/9=55
Hence, the following statement is false.
One zero is - 1
because p(-1) = (-1)^3 + (-1)^2 -4(-1)- 4 = 0
So one factor of p(x) is x + 1
Dividing p(x) by x + 1 gives the quotient
x^2 - 4
x - 2)(x + 2) = 0
x = 2, -2
The zeroes are -2,-1 and 2