Question

How many solutions does a triangle with side lengths a = 6, a equals 110 degree , and b = 10 have?

Answer 1

The Answer is 0. No solution

Answer 2

Answer:

No solution

Step-by-step explanation:

We are given some dimension of triangle.

a=6

∠A=110°

b=10

Using sine law, we will find rest part of the triangle.

$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$

Substitute the value into formula

$\dfrac{6}{\sin 110^\circ}=\dfrac{10}{\sin B}=\dfrac{c}{\sin C}$

$\dfrac{6}{\sin 110^\circ}=\dfrac{10}{\sin B}$

$\sin B=1.56$

$\angle B=\sin^{-1}(1.56)$

$\angle B=\text{Not Possible}$

Because value of sine can't be more than 1.

No solution for triangle. No such triangle form.

Hence, The number of triangle for given info is zero