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3 years ago

Solve the equation for real c variable. R-C=p

Mathematics

1 answer:

tekilochka [14]3 years ago

3 0

C = R - p

add C to both sides

R = C + p

subtract p from both sides

R - p = C ⇒ C = R - p

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If j ll k which could be one of the angle measures A.25 B.37 C.60 D.84

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Answer:

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2 years ago

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The hypotenuse of a right triangle is 34 inches. One leg of the triangle is 14 inches less than the other leg. In simplified for

Karolina [17]

You can use the equation

${(x + 14)}^{2} + {x}^{2} = {34}^{2}$
to find the lenth of the legs

x = leg 1
x + 14 = leg 2

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3 years ago

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I need fast help with step by step <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7B%5Cfrac%7B3x-1%7D%7Bx%2B1%7D

Ganezh [65]

Answer:

1.38 to the nearest hundredth.

Step-by-step explanation:

Dividing:

x + 1 ) 3x - 1 ( 3

3x + 3

-4

so (3x - 1) / (x + 1) = 3 - 4 / x+ 1

Integral of (3 - 4 / x+1 ) = 3x - 4 ln(x + 1)

Between limits of 1 and 2 we have:

(3(2) - 4 ln 3) - (3 - 4 ln2)

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3 years ago

12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

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3 years ago

Please help me im really bad only higher grades can answer

myrzilka [38]

Positive sorry if it’s wrong good luck

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2 years ago

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