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Natasha2012 [34]
3 years ago
9

The rule RO, 90° • T-1, 1(x, y) is applied to ΔBCD to produce ΔB"C"D". Point B" of the final image is at (–4, 1).

Mathematics
2 answers:
jenyasd209 [6]3 years ago
6 0
The coordinates of point B on the pre-image is (2, 3) :

RO, 90°
Original coordinates: (2 , 3)
Angle of roration 90
x-new = x*cos( θ )-ysin( θ ) , θ = 90
= 2cos(90) - 3sin(90)
x-new = (2)(0)-(3)(1) = -3
y-new = x*sins( θ)+ycos( θ ) , θ = 90
= 2sin(90) + 3cos(90)
y-new = (2)(1)+(3)(0) = 2
Coordinates after rotation (-3,2)

T-1
(-3,-1,2-1)
(-4,1)

1(-4,1) = (-4,1)
alexgriva [62]3 years ago
5 0
The rule RO, 90° • T-1, 1(x, y) is applied to ΔBCD to produce ΔB"C"D" means that it starts with T-1, 1(x, y) and ends with RO, 90° (counter-clockwise).

Working backward, we have

 RO, -90° (clockwise) which gives

(-4,1) => (1,4)

then reverse T-1, 1(x, y), which is T1, -1(x, y):

(1,4) => (2,3)


so ans is C


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<h2><u>=</u> <u>   57 / 514  </u>    <u>(Decimal: 0.110895)</u></h2>

Step-by-step explanation:

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<u>(Decimal: 0.110895)</u>

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<h2><u>And if that is not what you are looking for here: </u></h2><h2><u></u></h2>

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Multiply both sides of the equation by  

14.14  ⋅  x /14 =  14 ⋅ 5 /7

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Tap for fewer steps...

Cancel the common factor of  14 .  

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x = 14 ⋅ 5 /7

Simplify  14 ⋅  5/ 7 .

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