if it is solution point (4, –2) must satisfy both equations
(1) –3x – 2y = –8-->-3*4-2*(-2)=-8
-12+4=-8 then-->-8=-8 ok
(2) y = 2x – 5
-2=2*4-5=3---------->-2 is not 3

the point (4, –2) is not solution of the system of equations

6 0

3 years ago

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Find the (real-valued) general solution to the differential equation. z′′+5z′=0

andrew-mc [135]

Try this solution:1. to make up the characteristic equation:α²+5α=0; $\left[\begin{array}{ccc} \alpha=0 \\ \alpha =-5\\\end{array}$ 2. to make up the final answer:y=C₁+C₂e⁻⁵ˣ

7 0

3 years ago

A policyholder has probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims. C

Sladkaya [172]

Answer:

0.89.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to aid in the solution to this question or problem. So, the data or parameters are;

(1). "probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims."

(2). " distributed on the interval [0,60] and are independent."

(3). "The insurer covers 100% of each claim."

So, taking (1) above we will have;

(Total probability= 0.7 + 0.2 + 0.1 = 0.1)

A = { (0.7 × 0)^2 + (0.2 × 1)^2 + ( 0.1 × 2)^2 =( 0.4) +( 0.4) = 0.8.

0.8 + total probability = 0.8 + 0.1 = 0.9.

So, from the question, we are to "Calculate the probability that the total beneﬁt paid to the policyholder is 48 or less."

Hence, P< 48/A = P < 48/0.9 = P < 53.33.

Thus, 53.33/60 = 0.89.

6 0

3 years ago