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sergiy2304 [10]
3 years ago
14

|2x-3| < 9 solve for x

Mathematics
2 answers:
Misha Larkins [42]3 years ago
7 0
|2x-3| < 9\iff2x-3 < 9\ \wedge\ 2x-3 > -9\\\\2x < 9+3\ \wedge\ 2x > -9+3\\\\2x < 12\ \wedge\ 2x > -6\\\\x < 6\ \wedge\ x > -3\\\\\\x\in(-3;\ 6)

Inessa [10]3 years ago
5 0
|2x-3| < 9  \\ \\2x-3 < 9 \ \ and \ \ 2x-3 > -9  \\ \\ 2x  < 9 +3 \ \ and \ \ 2x  > -9 +3 \\ \\ 2x  < 12\ \ and \ \ 2x  > -6 \\ \\  x  < 6\ \ and \ \ x  > - 3 \\ \\  x \in (-3,6)

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The formula associated with the focus of an ellipse is given as;

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Learn more about Pythagorean theorem here:

brainly.com/question/654982

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