we have

we know that

so

two solutions
<u>first solution </u>


the first solution is the interval---------> (-1,∞)
<u>second solution</u>




the second solution is the interval---------> (-∞,-1)
therefore
the solution is all real numbers except the number 
the answer in the attached figure
Answer: x = 7
Step-by-step explanation:
4(2x-3) = 6x+2 <--distribute the 4
8x - 12 = 6x + 2 <---add 12 to both sides
8x = 6x + 14 <--- subrtract 6x from both sides
2x = 14 <--- divide by two
x = 7
This is (x - 6)*x^1/2(x + 3)
= x^1/2 (x^2 - 3x - 18)
= x^(5/2) - 3x^(3/2) - 18x^(1/2)
The correct answer is true since an integer is simply just a number
<h2>
Explanation:</h2><h2>
</h2>
An irrational number is a number that can't be written as a simple fraction while a rational number is a number that can be written as the ratio of two integers, that is, as a simple fraction. So in this case we have the number 2 which is ration, and we can multiply it by an irrational number
such that the product is an irrational number. So any irrational number will meet our requirement because the product of any rational number and an irrational number will lead to an irrational number. For instance:
