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lesantik [10]
3 years ago
11

Use the remainder theorem to determine whether x=-4 is a solution of x^6+5x^5+5^4+5^3+2x^2-10x-8.​​

Mathematics
1 answer:
kykrilka [37]3 years ago
4 0

Hello haohaoxNienie!

\huge \boxed{\mathbb{QUESTION} \downarrow}

Use the remainder theorem to determine whether x = - 4 is a solution of x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

<em><u>Refer </u></em><em><u>to</u></em><em><u> the</u></em><em><u> attached</u></em><em><u> picture</u></em><em><u>.</u></em>

<h3><u>Steps </u><u>:</u><u>-</u></h3>
  1. First find the divisor using the given information (x = - 4).
  2. Now, divide x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8 by x + 4.
  3. We'll get the remainder as 0.
  4. Using the remainder theorem & solving it, we'll get LHS & RHS as 0.
  5. Hence proved.

<u>Answer</u><u> </u><u>:</u><u>-</u><u> </u>Yes, x = - 4 is a solution of x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8.

__________________

Hope it'll help you!

ℓu¢αzz ッ

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