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ch4aika [34]
3 years ago
10

One cell phone plan charges $20 per month plus $0.15 per minute used. A second cell phone plan charges $35 per month plus $0.10

per minute used. Write and slice an equation to find the number of minutes you must talk to have the same cost for both calling plans.
Mathematics
1 answer:
erica [24]3 years ago
6 0

Answer:

300 minutes

Step-by-step explanation:

Let

x----> the numbers of minutes used

y ---> the cost per month

we know that

<em>First cell phone plan</em>

y=0.15x+20 ---> equation A

<em>Second cell phone plan</em>

y=0.10x+35 ---> equation B

equate the equation A and equation B

0.15x+20=0.10x+35

Solve for x

0.15x-0.10x=35-20

0.05x=15

x=15/0.05

x= 300 minutes

Find the cost y

y=0.15(300)+20 =$65

That means

For x=300 minutes

The cost for both calling plans is y=$65

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Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: F_{r} (t) that correspond to the force of resistance on the mass by the action of the spring and F(t) that is an external force with unknown direction (that does not specify in the enounce).

For determinate F_{r} (t) we can use Hooke's Law given by the formula F_{r} (t) = k y(t) where k correspond to the elastic constant of the spring and y(t) correspond to  the relative displacement of the mass-spring system with respect of his rest state.

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F_{r} (t) = ky(t) = 441.45y(t)

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We know from the problem that there's not initial displacement and initial velocity, so... y(0)=0 and y'(0)=0

Finally the Initial Value Problem that models the situation describe by the problem is

\left \{ 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = \frac{+}{} 170 cos(5t) \atop {y(0)=0, y'(0)=0\right.

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Answer:

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