m<1 = 59°
m<2 = 90° - 59° = 31°
m<3 = 59°
m<4 = 31°
m<5 = 31°
m<6 = 59°
m<7 = 180° - (31° + 31°) = 118°
m<8 = 180° - 118°= 62°
m<9 = m<8 = 62°
m<10 = m<7 = 118°
m<11 = 31°
Answer:
The answer to your question is below
Step-by-step explanation:
In Mayan notation there are only 3 symbols
dot . means one
line --- means five
snail means zero
And the are three levels, the lower means x 1
the first means x 20
the second means x 400
the higher means x 8000
Then, 135 is lower than 400, so we must start in the first level and need to divide 135 by 20. 6
20 135
15
Finally place 6 in the fist level and 15 in the lower lever, like this
And 120 + 15 = 135.
Answer: x is 12
Step-by-step explanation:
For directly proportional relationship, both variables change in the same direction. It means that an increase in one variable will result to an increase in the other variable. A decrease in one variable will result to a decrease in the other variable.
y and x have a proportional relationship,
We will introduce a proportionality constant and replace the proportionality symbol with an equal to symbol. Thus
y = kx
When y is 12, x is 8
Substituting into the equation,
12 = k × 8
k = 12/8 = 1.5
The equation becomes
y = 1.5x
The value of x when y is 18 will be
18 = 1.5x
x = 18/1.5 = 12
Answer:
![x= 6](https://tex.z-dn.net/?f=x%3D%206)
Step-by-step explanation:
RT = RS + ST
![48=5x+3x](https://tex.z-dn.net/?f=48%3D5x%2B3x)
![48=8x](https://tex.z-dn.net/?f=48%3D8x)
Swap sides:
![8x=48](https://tex.z-dn.net/?f=8x%3D48)
Divide both sides by 8:
![\frac{8x}{8} =\frac{48}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B8%7D%20%3D%5Cfrac%7B48%7D%7B8%7D)
![x=6](https://tex.z-dn.net/?f=x%3D6)
For a cone to fit perfectly inside the can it needs to have the same base circle size and same height.
Work out the height of the can first:
![height = \frac{volume}{ \pi *radius^{2} }](https://tex.z-dn.net/?f=height%20%3D%20%20%5Cfrac%7Bvolume%7D%7B%20%5Cpi%20%2Aradius%5E%7B2%7D%20%7D%20)
![height = \frac{15}{ \pi *1^{2} }](https://tex.z-dn.net/?f=height%20%3D%20%20%5Cfrac%7B15%7D%7B%20%5Cpi%20%2A1%5E%7B2%7D%20%7D%20)
![height = 4.77](https://tex.z-dn.net/?f=height%20%3D%204.77%20)
This means your cone can have a max height of 4.77 and the same base circle (diameter of 2 / radius 1).
Work out the volume of cone:
![Volume = \pi * radius^{2} * \frac{height}{3}](https://tex.z-dn.net/?f=Volume%20%3D%20%20%5Cpi%20%2A%20radius%5E%7B2%7D%20%2A%20%5Cfrac%7Bheight%7D%7B3%7D%20)
![Volume = \pi * 1^{2} * \frac{4.77}{3}](https://tex.z-dn.net/?f=Volume%20%3D%20%20%5Cpi%20%2A%201%5E%7B2%7D%20%2A%20%5Cfrac%7B4.77%7D%7B3%7D%20)
![Volume = 5 \pi * radius^{2} * \frac{height}{3}](https://tex.z-dn.net/?f=Volume%20%3D%205%20%20%5Cpi%20%2A%20radius%5E%7B2%7D%20%2A%20%5Cfrac%7Bheight%7D%7B3%7D%20)
The volume of your cone which fits perfectly inside the can is 5.