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vesna_86 [32]
3 years ago
6

A carpenter makes wooden chairs.

Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

Is there supposed to be a graph somewhere?

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By coincidence, Kimberly's Paint Supplies sold equal quantities of two paint colors yesterday: yellow and blue. All yellow paint
Vlad1618 [11]

Answer:

36 liters

Step-by-step explanation:

We solve this question using the least common multiple method

Find and list multiples of the liter the blue paint comes in the liters the yellow paint comes in. We find the first common multiple is found. This is the least common multiple.

Multiples of 9:

9, 18, 27, 36, 45, 54

Multiples of 12:

12, 24, 36, 48, 60

Therefore,

LCM(9, 12) = 36

Hence, the smallest amount of each paint color the store must have sold is 36 liters

8 0
3 years ago
Jan graphed her house and the local parks on a coordinate plane. Her house is located at (-5, 6), Park A is at (4, 6), and Park
Ulleksa [173]
C the park B is the furthest at 11 blocks away
8 0
2 years ago
Read 2 more answers
What is the solution set of 4x^2-36= 0?<br><br> (-3)<br> (3)<br> (-3,3)
ololo11 [35]

Answer:

(-3, 3).

Step-by-step explanation:

4x^2-36= 0

4x^2 = 36    Taking square roots of both sides:

2x = +/- 6

x = +/- 3.

6 0
3 years ago
Read 2 more answers
La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0
3 years ago
X^lg(x)=100^x find x
Wittaler [7]

x^lg(x)=100^x<span>
</span>


X^lg(x)=100^x:x  |Solve \ for \ x|


<span>|Use \ logarithms \ of \ both \ sides \ of \ the \ base \ 10|&#10;&#10;</span>

<span>
</span>

<span>lg (x ^ lg (x)) = lg (100x)&#10;&#10;</span>

<span>
</span>

<span>lg ^ 2 (x) = 2 + lgx</span>

<span>
</span>

lg 2 ^ x-lg x -2 = 0


lg x = 2 x = 100


lg x = -1 x = \dfrac{1}{10} = 0.1

3 0
3 years ago
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