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Mariana [72]
3 years ago
9

The inequality 10x ≤ –0.6x + 7 can be broken into two related inequalities. Review the graphs of the two related inequalities.

Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:

B) -3

Step-by-step explanation:

just got it right on edge

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Tony bought x cans of tennis balls for $3 each. He bought the same number of water bottles for $5. He also
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What are you asking exactly?
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2 years ago
4 students equally share 2/3 of a pizza
oee [108]

\frac{2}{3} *4

=\frac{2*4}{3}

=\frac{8}{3}

2.67 or 2 \frac{2}{3}

6 0
3 years ago
If you flipped a fair coin 18 times, about how many times would you expect heads to appear? HELP ME PLEASE!!!!!!!
Andrei [34K]

Answer:

9 or 3.8x10^-6

Step-by-step explanation:

By flipping a coin you'd look at how many times a head could appear (1/2) and multiply that by the 18 times.

Another explanation:

I'm not sure on this but would you raise 1/2 to the 18th power?

4 0
3 years ago
What is the surface area of 5, 8, and 3
Rashid [163]

Answer:

158

Step-by-step explanation:

5*8=40

8*3=24

3*5=15

Each of these measurements gets added twice, becasue there are 6 faces on a rectangular prism.

40 + 40 + 24 + 24 + 15 + 15 = 158

5 0
2 years ago
Read 2 more answers
The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c
Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 \rm{in^3}

Step-by-step explanation:

The linearization or linear approximation of a function f(x) is given by:

f(x_0+dx) \approx f(x_0) + df(x)|_{x_0} where df is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh

Taking R_0=1.5 inches and h=3 inches and evaluating the partial derivatives we obtain:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh

substituting the values and taking dx=0.1 and dh=0.3 inches we have:

V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3}  + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}

Therefore the change in volume is estimated to be 17.20 \rm{in^3}

4 0
2 years ago
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