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3 years ago

The inequality 10x ≤ –0.6x + 7 can be broken into two related inequalities. Review the graphs of the two related inequalities.

Mathematics

1 answer:

pishuonlain [190]3 years ago

7 0

Answer:

B) -3

Step-by-step explanation:

just got it right on edge

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Tony bought x cans of tennis balls for $3 each. He bought the same number of water bottles for $5. He also

NeX [460]

What are you asking exactly?

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2 years ago

4 students equally share 2/3 of a pizza

oee [108]

$\frac{2}{3} *4$

= $\frac{2*4}{3}$

= $\frac{8}{3}$

2.67 or 2 $\frac{2}{3}$

6 0

3 years ago

If you flipped a fair coin 18 times, about how many times would you expect heads to appear? HELP ME PLEASE!!!!!!!

Andrei [34K]

Answer:

9 or 3.8x10^-6

Step-by-step explanation:

By flipping a coin you'd look at how many times a head could appear (1/2) and multiply that by the 18 times.

Another explanation:

I'm not sure on this but would you raise 1/2 to the 18th power?

4 0

3 years ago

What is the surface area of 5, 8, and 3

Rashid [163]

Answer:

158

Step-by-step explanation:

5*8=40

8*3=24

3*5=15

Each of these measurements gets added twice, becasue there are 6 faces on a rectangular prism.

40 + 40 + 24 + 24 + 15 + 15 = 158

5 0

2 years ago

Read 2 more answers

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$

Therefore the change in volume is estimated to be 17.20 $\rm{in^3}$

4 0

2 years ago