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Leya [2.2K]
4 years ago
12

Azul performed an experiment to determine which crank powered radio works best. He cranked 15 randomly selected radios of each b

rand 30 times at the same speed and measured how long the radios played in minutes before running out of power. The result of the experiment is displayed in the box plot below.
Mathematics
2 answers:
choli [55]4 years ago
6 0
50% of streamline crank radios are likely to play 30 minutes or longer after 30 cranks, while only 25% of secure hike emergency radios ARE LIKELY to play 30 minutes or longer after 30 cranks.
gizmo_the_mogwai [7]4 years ago
6 0
50% of X-Treamline Crank Radios are likely to play 30 minutes or longer after 30 cranks, while only 25% of Secure Hike Emergency Radios are likely to play 30 minutes or longer after 30 cranks
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I'll do problem 13 to get you started.

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4\left(\frac{2}{7}\right)^n\\\\4\left(\frac{2}{7}\right)^n*1\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{0}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1-1}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1}*\left(\frac{2}{7}\right)^{-1}\\\\4*\left(\frac{2}{7}\right)^{1}\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{-1}\\\\\frac{8}{7}\left(\frac{2}{7}\right)^{n-1}\\\\

This is so we can get the expression in a(r)^(n-1) form

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Note that -1 < 2/7 < 1, which satisfies the condition that -1 < r < 1. This means the infinite sum converges to some single finite value (rather than diverge to positive or negative infinity).

We'll plug those a and r values into the infinite geometric sum formula below

S = a/(1-r)

S = (8/7)/(1 - 2/7)

S = (8/7)/(5/7)

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S = 8/5

S = 1.6

------------------------

Answer in fraction form = 8/5

Answer in decimal form = 1.6

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