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valina [46]
3 years ago
13

A square pyramid of base 3cm by 3cm is made from 18cm3 of clay.

Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

Answer:

6 cms.

Step-by-step explanation:

Volume of the pyramid = 1/3 * area of base * height

= 1/3 * 3*3 * h = 18

1/3 * 9 * h = 18

3h = 18

h = 6 cm

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20 Points for 4 questions. BRAINLIEST also
pav-90 [236]

Answer:

Image #1: -8 and 8

Image #2: -17 and -1

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Image #4: -10±5√2

8 0
3 years ago
What number should be added to the expression x^2 + 6x to change it into a perfect square trinomal
alexandr402 [8]
Hello.

The correct is answer is 9.

You have to do half of 6 (3) and then square it that equals 9

So it should be <span> x^2 + 6x +9

Have a nice day</span>
5 0
3 years ago
Mrs Perry shares out 21 biscuits between
avanturin [10]

Answer:

Gemma gets 3 biscuits

Zak gets 18 biscuits

Step-by-step explanation:

1:6 = 1+6

= 7

1/7 * 21 = 3

6/7 * 21 = 18

4 0
3 years ago
Read 2 more answers
The temperature in San Antonio, Texas is currently 77 degrees Fahrenheit and increasing by 3 degrees per hour. The current tempe
user100 [1]

Answer:

1)3 2)86

Step-by-step explanation:

3h+77=SA AND 92-2h=MB

3h+77=92-2h

-77. = -77

3h= 15-2h

+2h=+2h

5h=15

H=3

3 0
3 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
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