Problem 1
Answer: Closer to 1
Explanation:
There are 20 gumballs total. Half of this is 20/2 = 10 gumballs. If there's more than 10 of one color, then the probability of getting that color is closer to 1, than it is to 0. Here we have 12 pink which is greater than 10, so that's why the answer is closer to 1.
================================================
Problem 2
Answer: Closer to 0
Explanation:
The amount of green (3) is less than 10, so that's why the probability is closer to 0 than it is to 1. We can see that 3/20 = 0.15 is less than 0.50
================================================
Problem 3
Answer: Closer to 0
Explanation:
We have a similar situation compared to problem 2. This time we have 5/20 = 0.25 which is less than 0.50
================================================
Problem 4
Answer: 48% chance; fairly likely
Explanation:
We have 12 green out of 25 total, so the probability of choosing green is 12/25 = 0.48 = 48%. While this probability is not over 50%, I still say it's fairly likely considering the other colors lead to smaller probabilities. For instance, purple has a chance of 6/25 = 0.24 = 24% and orange has a probability of 2/25 = 0.04 = 4%, both of which are smaller than 48%
The equation would be 90/18 which would give you the cost of 5 dollars per rose
the answer is 153.86 ft squared
= the formula for the area of a circle is A=πr2
= area = pi x radius squared
= the radius is 7 feet, square that to get 49
= multiply 49 by pi to get the area: 153.86 square feet
153.86 ft squared
The median is 11, so 11 is part of the data set. We have an odd number of values (5) which is why the median is part of the data set.
The mode is 12. The value 12 shows up the most times. Let's say it shows up twice. So far the data set is {11, 12, 12}
Let's introduce two more numbers x and y
The new data set is {x, y, 11, 12, 12}
Add up the five values and then divide by 5. We want this result to be equal to 10
(x+y+11+12+12)/5 = 10
(x+y+35)/5 = 10
x+y+35 = 10*5
x+y+35 = 50
x+y = 50-35
x+y = 15
So we don't know what x or y is, but we know that they must add to 15. So all you have to do is list two numbers that add to 15. One such pair is x = 6 and y = 9. Another pair is x = 7 and y = 8. There are infinitely many possibilities if you can use any real number.
So one possible set is {6, 9, 11, 12, 12}
Another possible set is {7, 8, 11, 12, 12}
Answer:
3,1
Step-by-step explanation:
