Answer:
203 rpm
Step-by-step explanation:
The speed of the larger gear can be calculated using the following equation:
<u>Where</u>:
ω: is the angular velocity of the motor = 700 rpm
R: is the gear ratio
The gear ratio is the following:
<u>Where:</u>
n(a): is the number of teeth on the small gear = 12 teeth
n(b): is the number of teeth on the larger gear = 42 teeth
The gear ratio is:
Now, the speed of the larger gear is:
Therefore, the speed of the larger gear is 203 rpm.
I hope it helps you!
Answer:
v=√
m
d
or v=−√
m
d
Step-by-step explanation:
Answer:
Substitute in the values of both given coordinates & form 2 equations:

Find the value of B from the equation 2A - B = 1:

Substitute in the B-value to the other equation:

Find the B-value using the equation from before:
Therefore the equation Ax + By = 1 would equal:

<span>n = 5
The formula for the confidence interval (CI) is
CI = m ± z*d/sqrt(n)
where
CI = confidence interval
m = mean
z = z value in standard normal table for desired confidence
n = number of samples
Since we want a 95% confidence interval, we need to divide that in half to get
95/2 = 47.5
Looking up 0.475 in a standard normal table gives us a z value of 1.96
Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula
0.0001 = z*d/sqrt(n)
Substitute the value z that we looked up, and get
0.0001 = 1.96*d/sqrt(n)
Substitute the standard deviation that we were given and
0.0001 = 1.96*0.001/sqrt(n)
0.0001 = 0.00196/sqrt(n)
Solve for n
0.0001*sqrt(n) = 0.00196
sqrt(n) = 19.6
n = 4.427188724
Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>