Raíz cuadrada de 864
Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:
The general equation of ellipse is given as, x2a2+y2b2=1 x 2 a 2 + y 2 b 2 = 1 , where, a is length of semi-major axis and b is length of semi-minor axis.
centro: (0,0)
focus : (0, -√28) , (0, √28)
eje conjugado = 2√3
por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:
de los focos podemos obtener que: √28
y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:
b = √3
podemos utilizar la siguiente fórmula para obtener a:
si despejamos a en la ecuación obtenemos lo siguiente:
ahora podemos sustituir los valores:
a=5
así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:
si graficamos la hipérbola, queda como en el documento adjunto.
To learn more hipérbola
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Answer:
10 weeks
Step-by-step explanation:
205+2t=195+3t
-2t -2t
205=195+t
-195 -195
10=t
70,266 I think let me know pls
<u>Answer:</u>
The correct answer option is: Each x value has one and only one y value.
<u>Step-by-step explanation:</u>
A relationship from a set of inputs to a set of outputs where each input has exactly one corresponding output value is said to be a function.
Here, we are given
which happens to be a function as no x value is repeated and there is only one corresponding y value to it.
Therefore, option c is the correct answer.
Answer: Explanation below.
Step-by-step explanation:
First of all you need to know how to convert a logarithm into an exponential expression. The property is:

This is the same as: 
Example 1:

We are trying to find what to raise 9 to, in order to get a result of 9.

When you have same bases, you equal exponents.

Therefore; 
Example 2:


In this case, we have to make sure both sides have the same base. 32 can have a base of 2 if expressed as:
which is 2*2*2*2*2
Rewriting this example we have;

Since we have the same base, we equal exponents.

Therefore; 
Example 3:


729 can have a base of 3 if expressed as: 

